Solve 2 Equations: 8x-4=9x+6,-x=10

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SUMMARY

This discussion addresses solving two equations: 8x - 4 = 9x + 6 and -x = 10, along with the addition of complex numbers. The correct approach involves separating real and imaginary components, as demonstrated in the example (-9 + 3i) + (4 + 5i). The final result of the complex addition is expressed as 5/8 for the imaginary part, confirming the solution methodology for complex numbers.

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aarce
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4(2x-1)=3(3x+2)

step 1: 8x-4=9x+6
step 2: -x=10
step 3: ?
 
Last edited:
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Your thread title and post content show two different problems...which one is correct? And what have you tried? I ask because we can better give you help if we see what you have tried as this gives us an indication of where you're stuck or may be going wrong.
 
You can treat imaginary parts and real parts separately - they add in the same way "regular" numbers do. We'll be able to help you more if we know where you're stuck :)
 
Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.
 
GeraldArgue said:
Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.

I believe the OP was supposed to express the sum of the two given complex numbers in the form $a+bi$ where:

$$i\equiv\sqrt{-1}$$

:D
 

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