MHB Solve 2 Equations: 8x-4=9x+6,-x=10

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The discussion revolves around solving two equations, but there is confusion as the title and content present different problems. The equations mentioned include 8x-4=9x+6 and -x=10, while the actual focus shifts to adding complex numbers. The solution provided involves combining the real and imaginary parts of the complex numbers (-9+3i) and (4+5i), resulting in 8i=5. The final answer expresses the imaginary unit i as 5/8, indicating a misunderstanding of the original equations. Clarification on the intended problem would enhance the assistance provided.
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4(2x-1)=3(3x+2)

step 1: 8x-4=9x+6
step 2: -x=10
step 3: ?
 
Last edited:
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Your thread title and post content show two different problems...which one is correct? And what have you tried? I ask because we can better give you help if we see what you have tried as this gives us an indication of where you're stuck or may be going wrong.
 
You can treat imaginary parts and real parts separately - they add in the same way "regular" numbers do. We'll be able to help you more if we know where you're stuck :)
 
Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.
 
GeraldArgue said:
Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.

I believe the OP was supposed to express the sum of the two given complex numbers in the form $a+bi$ where:

$$i\equiv\sqrt{-1}$$

:D
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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