Solve 2x + y + y' x = 3y^2 y', why is this wrong?

1. Jun 17, 2008

Ry122

2x+y+(dy/dx)x=3y^2(dy/dx)
This is wrong:
(dy/dx)(x-3y^2)=-2x-y
This is right:
2x+y=(3y^2-x)(dy/dx)

2. Jun 17, 2008

scottie_000

Those two equalities are actually the same, so I'm not sure "right" and "wrong" really apply.
The only difference is that the second is the negative of the first.
If you move each side of the first equality over the equals sign you will get the second

3. Jun 17, 2008

Defennder

Yeah, scottie_000 is right. Multiply the first by -1 and you'll get the second.

4. Jun 18, 2008

Ry122

So either answer would be correct in an exam?

5. Jun 18, 2008

Defennder

Of course, if they were strictly equivalent and your teachers don't mind.