Solve 2xyy'=4x^2+3y^2 w/ Substitution

[Mechdude]

how do i transform this to linear
$$2xyy' = 4x^2 +3y^2$$
using substitution

 

[HallsofIvy]

This can be written as
$$\frac{dy}{dx}= \frac{4x^2+ 3y^2}{2xy}= 2\frac{x}{y}= \frac{3}{2}\frac{y}{x}$$

Try the substitution u= y/x.

 

[Mechdude]

so if u=y/x would this be right? $$\frac{du}{dx}= \frac{-dy}{dx} \frac{1}{x^2}$$

you third equal sign should be a + sign i believe