Solve 6 Letter Words: 3 Consonants & 3 Vowels from "Circumference

  • Thread starter Thread starter novince
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the number of six-letter words that can be formed from the letters of "circumference," specifically using three consonants and three vowels. Participants emphasize the importance of understanding permutations and combinations to solve this problem. The word contains 8 consonants and 5 vowels, and the solution involves selecting and arranging these letters while adhering to the constraints of letter frequency. Clarifications regarding the limits on letter usage are also addressed.

PREREQUISITES
  • Understanding of permutations and combinations
  • Familiarity with the letters in "circumference" (8 consonants, 5 vowels)
  • Basic probability concepts
  • Ability to formulate and approach combinatorial problems
NEXT STEPS
  • Study the principles of permutations and combinations in depth
  • Practice problems involving letter arrangements and constraints
  • Explore combinatorial probability techniques
  • Review examples of similar word formation problems
USEFUL FOR

This discussion is beneficial for students tackling combinatorial problems, educators teaching probability and permutations, and anyone interested in word formation challenges using specific letter constraints.

novince
Messages
4
Reaction score
0

Homework Statement


"Q.Find the no: of six letter words each consisting of three consonants and three vowels that can be formed using the letters of the word 'circumference'."
If you have cracked it please tell me how you did it.

Homework Equations


you have to be familiar with permutation and combination to solve it.


The Attempt at a Solution

 
Physics news on Phys.org
i know nothing about probability so this is probably wrong.

<< post edited by berkeman to remove work done for the OP >>

also, if by luck my method is right there is one ambiguity. if your teacher doesn't want you to be limited by the number of times the vowel or consonant appears in the word. I assumed that he does want that limit.
 
Last edited by a moderator:
xcvxcvvc said:
i know nothing about probability so this is probably wrong.

<< post edited by berkeman to remove work done for the OP >>

also, if by luck my method is right there is one ambiguity. if your teacher doesn't want you to be limited by the number of times the vowel or consonant appears in the word. I assumed that he does want that limit.

Please don't do the OP's work for them.

novince -- you need to show us an attempt at a solution before we can offer tutorial help. How would you approach this problem?
 
berkeman said:
Please don't do the OP's work for them.

novince -- you need to show us an attempt at a solution before we can offer tutorial help. How would you approach this problem?

Sorry :X. Does that mean I got it right? That would make me feel good - at least for a moment :P.
 
xcvxcvvc said:
Sorry :X. Does that mean I got it right? That would make me feel good - at least for a moment :P.

LOL. I didn't look closely at it, but it looked way too good to leave posted. :smile:
 
xcvxcvvc said:
Sorry :X. Does that mean I got it right? That would make me feel good - at least for a moment :P.

BTW, feel free to give a couple hints to get the OP going. Just not all that stuff in the middle of your post... Thanks.
 
Well, you know you have 8 consonants and 5 vowels in the word 'circumference'. You then need to pick 3 of the consonants and 3 of the vowels and arrange them.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
7
Views
7K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
2K