Solve a Complex Number Question: z = a/b and 1/(a+b) = 1/a + 1/b?

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Homework Help Overview

The discussion revolves around a problem involving complex numbers, specifically the relationship defined by z = a/b and the equation 1/(a+b) = 1/a + 1/b. Participants are exploring how to manipulate these expressions to find z.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods to manipulate the given equations, including combining fractions and cross-multiplying. Some express confusion about the goal of the problem, questioning whether z should be expressed in different forms.

Discussion Status

The discussion includes attempts to derive z through algebraic manipulation, with some participants suggesting specific strategies such as multiplying both sides by (a+b) and expressing terms in relation to z. There is a sense of progress as participants share their attempts and insights.

Contextual Notes

Some participants mention a lack of prior exposure to similar problems in class, which may influence their approaches. There is also a reference to checking results, indicating an ongoing verification process.

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Homework Statement

If [tex]z = \frac{a}{b}[/tex] and [tex]\frac{1}{a + b} = \frac{1}{a} + \frac{1}{b}[/tex], find z.



Homework Equations

I'm pretty sure z is a complex number.



The Attempt at a Solution

I have no idea where to start. The teacher did nothing like this in class. I tried something that involved combining the fractions on the right hand side and then cross-multiplying with the fraction on the left hand side. I played around with that for a few minutes but it didn't give me anything.
 
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I am confused about what you are asking. z is defined. Are you trying to get z in different terms than above? Or perhaps in cartesian/standard or polar form?
 
lockedup said:
I tried something that involved combining the fractions on the right hand side and then cross-multiplying with the fraction on the left hand side. I played around with that for a few minutes but it didn't give me anything.

Keep playing. It works out.
 
Multiply both sides of your equation by (a+b) and try to reduce the right side to terms that are constants or a/b, or b/a. a/b=z. Doesn't that make b/a=1/z? Write it all in terms of z. Think 'quadratic equation'.
 
I think I got it. I substituted zb for a. I combined and cross multiplied again. I ended up with [tex]z = \frac{-1}{2} \pm \frac{i\sqrt{3}}{2}[/tex]

Now I need to check it...
 
It checks! w00t \O/
 

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