Solve Acceleration of Inclined Plane Given z,P,A

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Homework Help Overview

The problem involves a mass on an inclined plane and seeks to determine the acceleration of the inclined plane when both masses are released. The scenario is set in a frictionless environment, with variables including the mass of the incline, the mass on the incline, and the angle of the incline.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on both the small mass and the inclined plane, with attempts to derive expressions for acceleration. Questions arise regarding the correctness of the initial assumptions and the choice of reference frames.

Discussion Status

Participants are actively engaging with the problem, questioning the assumptions made about forces and accelerations. Some have suggested alternative approaches, such as considering different frames of reference, but no consensus has been reached regarding the correct method or solution.

Contextual Notes

There are indications of confusion regarding the vertical acceleration of the small mass, with participants noting that it is not simply equal to g due to the constraints of the inclined plane. The discussion also reflects on the implications of choosing different frames of reference for analysis.

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Homework Statement


a mass z is held on an incline plane with mass P. when the the masses are released, both objects begin to move and accelerate. find accell of the incline plane

GIVEN: z,P,angle A, surfaces are frictionless

solve in terms of these variables.

Homework Equations



f=ma

The Attempt at a Solution


i chose my positive x direction along the ground surface below the incline plane, toward the direction of its motion.

so first i solved for the small mass on top the normal force, which is the force which applied onto the incline plane by the small mass.

fnety=0=FNcosA - zg
FN= zg/cosA

now when i do the FBD of the incline plane the forces acting on it, are the normal (FN) which gives it an unbalanced force in the +X direction.

so i get the expression

fnetx= (z+P)a=FNsinA

subbing in the FN,i get

a= zgtanA/(z+P)

is this correct? if not can you tell me where i am going wrong.
 
Last edited:
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The small mass accelerates along the y direction. So Fnet is not zero along this direction.
 
Ahh I see..
Fnety=zg=FN-zgcosA
FN=2zg/cosA

Ans; 2zgtanA/(z+P)
 
The vertical acceleration of the small object is not g. It's not falling freely.
 
nasu said:
The vertical acceleration of the small object is not g. It's not falling freely.

would it make it more simple if i chose a different frame of reference.
 
You could work in the non-inertial frame of the moving inclined plane. But I am not sure it makes simpler. Depends how it is easier to visualize for you. In the inertial frame attached to the ground or in the moving frame.
 

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