Solve Angular Speed of Rotating Rod: Conservation of Energy

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Homework Help Overview

The discussion revolves around determining the angular speed of a rotating rod using principles of conservation of energy and angular motion. Participants are exploring the implications of varying angular acceleration as the rod swings through different angles.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the applicability of a formula for angular motion that assumes constant angular acceleration, given that the torque varies with the angle of inclination. They discuss the effectiveness of conservation of energy as a method that does not rely on constant acceleration.

Discussion Status

There is an active exploration of the problem, with participants providing insights into the nature of torque and angular acceleration. Some guidance has been offered regarding the limitations of certain formulas, and the conversation reflects a productive examination of the concepts involved.

Contextual Notes

Participants note that the original question involves initial conditions and that the changing angle affects the torque, which complicates the use of certain equations. There is an acknowledgment of the need for clarity around the assumptions made in the problem setup.

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The question is as the attachment...
May i know if i want to find the angular speed of the rod when it inclined at certain angle, or at horizontal, can i use the \varpi^2=\varpi_0^2+2\alpha\vartheta?

Attempt: I used it, and used conservation of energy, the latter produces right answer, but i don't know why first one won't work. Any clues?
 

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Hi rasensuriken! :smile:

I can't read your formula … but, looking at the .jpg, I don't think the angular acceleration, α, is constant (because the torque from the weight is different for different angles).

So a formula using constant α won't work! :smile:
 
tiny-tim is right, the author of the JPEG image made a mistake. He forgot that the torque is a cross product of radius and the force, which depends on the angle. And the angle changes as the whole thing swings down, so the alpha should be more like:
\tau = MG\frac{L}{2} \sin{\omega t}
Which, as you can see, depends on the time and so is not constant. The conservation of energy worked because it does not care about the acceleration at any point, but only on the initial and final conditions.
 
Hi kkrizka! :smile:

No, he didn't forget … he only asked for the inital values, for which his equations are correct.

The question in the OP is rasensuriken boldly going further! :smile:
 
tiny-tim said:
Hi kkrizka! :smile:

No, he didn't forget … he only asked for the inital values, for which his equations are correct.

The question in the OP is rasensuriken boldly going further! :smile:

Ah whoops, I've been reading too many phys problems lately and they are starting to get mixed up. :P
 
ya...i also just thought of that...the acceleration is not constant...because the L/2 relative to the center of mass keep on changing...thanks!
 

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