Solve Binomial Expansion Homework: (a) (1-x6)4, (b), (c) |x|<1

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SUMMARY

The discussion focuses on solving a binomial expansion homework problem involving the expression (1-x6)4 and finding specific coefficients in the expansions. The solutions provided include the expansion of (1-x6)4 yielding 1-4x6+6x12-4x18+x24, the coefficient of xr in (1-x)-4 as (r+1)(r+2)(r+3)/6, and the coefficient of x8 in ((1-x6)/(1-x))4 determined to be 125. The discussion highlights the importance of correctly applying binomial expansion techniques to derive these coefficients.

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Homework Statement



(a) Expand (1-x6)4
(b) Find the coefficient of xr, where r is a non-negative integer, in the expansion of (1-x)-4 for |x|<1.
(c) Using (a) and (b), or otherwise, find the coefficient of x^8 in the expansion of ((1-x6)/(1-x))4 for |x|<1.

(Answers:
(a) 1-4x6+6x12-4x18+x24
(b) (r+1)(r+2)(r+3)/6
(c) 125)

Homework Equations



Binomial Expansion: n(n-1)...(n-r+1)*xr/r!

The Attempt at a Solution



I can solve parts (a) and (b) but not part (c).

I tried (-4)(2+3)(2+2)(2+1)/6 = -40 but not correct.

Can anyone tell me how to solve it?

Thank you very much!
 
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Hi chrisyuen! :smile:
chrisyuen said:
(c) Using (a) and (b), or otherwise, find the coefficient of x^8 in the expansion of ((1-x6)/(1-x))4 for |x|<1.

(Answers:
(a) 1-4x6+6x12-4x18+x24
(b) (r+1)(r+2)(r+3)/6
(c) 125)

I tried (-4)(2+3)(2+2)(2+1)/6 = -40 but not correct.

Yes, that's x6 times x2

now what about 1 times x8? :wink:
 
tiny-tim said:
Hi chrisyuen! :smile:


Yes, that's x6 times x2

now what about 1 times x8? :wink:

Yes, I got it!

Thank you very much!
 

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