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anglum said:so then for the horizontal distance it is just 17 cos 50 (2.62)?
yes.
anglum said:so then for the horizontal distance it is just 17 cos 50 (2.62)?
anglum said:014 (part 1 of 2) 10 points
The speed of a point on a rotating turntable,
which is 0.131 m from the center, changes at a
constant rate from rest to 0.958 m/s in 1.95 s.
At t1 = 1.6 s, find the magnitude of the
tangential acceleration. Answer in units of
m/s2.
015 (part 2 of 2) 10 points
At t1 = 1.6 s, ¯find the magnitude of the total
acceleration of the point. Answer in units of
m/s2.
anglum said:ok 2 more problems if u don't mind?
#1
a rotating cylinder 10 miles long and 4.9 miles in radius is in space...
acceleration of gravity is 9.8m/s squared
what angular speed must the cylinder have so that the centripetal acceleration at its surface equals the free fall acceleration on earth?