Solve Circuits Homework: V=IR, 12V & 24V, 2-8 Ohms

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SUMMARY

The discussion focuses on solving a circuit homework problem involving Ohm's Law (V=IR) with a 12V and 24V battery configuration and resistors of 2, 4, and 8 Ohms. The user correctly calculates the current through R1 as 6 A and R2 as 3 A, leading to a total battery current of 9 A. The equivalent resistance of the circuit is determined using the formula for resistors in parallel and series, resulting in a total resistance of 4 Ohms for the battery. The user seeks confirmation on their calculations and the next steps in solving the circuit.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of series and parallel resistor configurations
  • Ability to perform calculations involving electrical current and resistance
  • Familiarity with circuit analysis techniques
NEXT STEPS
  • Learn how to calculate equivalent resistance for complex circuits
  • Study Kirchhoff's laws for current and voltage in circuit analysis
  • Explore the concept of voltage drops across resistors in parallel
  • Practice solving circuit problems using simulation tools like LTspice or Multisim
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Students studying electrical engineering, educators teaching circuit analysis, and anyone looking to improve their understanding of Ohm's Law and resistor configurations in electrical circuits.

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Homework Statement



http://img130.imageshack.us/img130/2366/capturewvb.jpg"

Homework Equations



V=IR

The Attempt at a Solution


Given Information
V I R
Battery
R1 12 V 2 ohm
R2 4 ohm
R3 24 V 4 ohm
R4 8 ohm

I can calculate the current of R1
V = IR
I = V/R
I = 12 V/2 = 6 A = I1

pl if I'm correct sense R1 and R2 are in parrallel and right next to the battery they should share the same voltage?

R2 = 12 V
from which I can calculate the current
V = IR
I = V/R = 12 V / 4 ohm = 3 A = I2

now the current for the whole batter should just be I1 + I2? = 6 A + 3 A = 9 A = I battery

I can fidn the R battery by doing

(1/R1 + 1/R2)^-1 + (1/R3 + 1/R4)^-1 = (1/2 + 1/4)^-1 + (1/4 + 1/8)^-1 = 4 ohm = R battery

am i doing this right were do i go from here?
 
Last edited by a moderator:
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Find the equivalent resistance of both of the two resistors in parallel then you'll have a circuit with two resistors in series and you should be able to find what you need to find.

The voltage drop across resistors in parallel will be equal but the current will not.
 

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