Solve Conical Pendulum: Find Speed, Period, Horiz. Comp., Rad. Accel.

Click For Summary
SUMMARY

The discussion focuses on solving the dynamics of a conical pendulum with a mass of 14.0 kg and a string length of 1.8 m, revolving at an angle of 28°. The speed of the object is calculated as 2.098 m/s, and the period of revolution is determined to be 2.53 seconds. Participants discuss the horizontal and vertical components of the tension in the string, using equations such as T = ma/sin(θ) for horizontal forces and T = mg/cos(θ) for vertical forces. The radial acceleration is derived from the formula a = v²/r, where r is calculated using trigonometric relationships.

PREREQUISITES
  • Understanding of conical pendulum dynamics
  • Familiarity with circular motion equations
  • Knowledge of trigonometry for calculating radius and components
  • Ability to apply Newton's laws of motion
NEXT STEPS
  • Study the derivation of conical pendulum equations
  • Learn about radial and tangential acceleration in circular motion
  • Explore the relationship between tension, mass, and gravitational force in pendulums
  • Investigate the use of trigonometric functions in physics problems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the mechanics of pendulums and circular motion dynamics.

coolskool
Messages
1
Reaction score
0
The Conical Pendulum


A small object of mass m is suspended from a string of length L = 1.8 m. The object revolves in a horizontal circle of radius r with constant speed v and angle = 28°

Find the speed of the object.
i found s=v=2.098.

Find the period of revolution, defined as the time interval required to complete one revolution.
i found it to be ... t=2.53

NOW...

For the conical pendulum described above, determine the following if m = 14.0 kg.
(a) the horizontal and vertical components exerted by the string on the object
(b) the radial acceleration of the object.

for H my equation is
T=ma/sin theta

and to find a=s/t
i take what i found in the previous problem right?
so s=v=2.098
and t=2.53?

and for Fv my equation is T=mg/costheta?

and then for part b...mv^2/r...
but what is r?

OKAY i found everything BUT the HORIZONTAL COMPONENT!
HELP
 
Last edited:
Physics news on Phys.org
For the first part I get a slightly different answer for the speed and period. your answers are round about the same as mine so perhaps just using different constants.

For parts a and b, you will have to go back to the circular motion equations and find the horizontal force being exerted on the bob.

part b the equation you have used is for force but you want acceleration. Remember F=ma. Also you should know what r is from the first part of the question. Its simply a matter of trigonometry (i.e. the pendulum string forms a right angled triangle with the vertical and horizontal and you know the hypotenuse and one of the angles).
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K