- #1
cheesecake91
- 1
- 0
μ[itex]^{2}[/itex][itex]\frac{d^{2}u}{dx^{2}}[/itex]+ae[itex]^{u}[/itex]=0
Boundary conditions: u(-L)=u(L)=u[itex]_{0}[/itex]
Solve by multiplying by [itex]\frac{du}{dx}[/itex] and integrating in x
I know you have to use substitution, but I keep going in circles.
Boundary conditions: u(-L)=u(L)=u[itex]_{0}[/itex]
Solve by multiplying by [itex]\frac{du}{dx}[/itex] and integrating in x
I know you have to use substitution, but I keep going in circles.