1. The problem statement, all variables and given/known data Two 9.4 k-ohm resistors are placed in series and connected to a battery. A voltmeter of sensitivity 1000 ohm/V is on the 3-V scale and reads 2 V when placed across either resistor. What is the emf of the battery? (Ignore it's internal resistance) 2. Relevant equations V=IR Emf = IR 3. The attempt at a solution First of all, I'm kind of unsure what "on the 3-V scale" means. My guess is that it means it takes 3 volts for a full-scale deflection of the voltmeter? Because it has a sensitivity of 1000 ohm/V and is reading 2 volts: I = V/R I = 2 V / 2000 ohm I = 1 x 10-3A Then I tried to find the total resistance of the circuit, first with the voltmeter and one resistor in parrallel and the other resistor in series: 1/R = 1/9.4 k-ohm + 1/2000 ohm = 1.65 k-ohm R = 1.65 k-ohm + 9.4 k-ohm = 11.1 k-ohm Finally, I went Emf = IR Emf= 1 x 10-3 (11.1 k-ohm) Emf = 11.1 V The correct answer is 10 V, so my answer is close, but I am unsure if that's just by chance, because I never actually used the fact that the voltmeter is "on the 3.0 V scale". I really have no idea if my thought process is correct for this problem, am I on the right track? Thanks!