Solve Equation: 3x - 7/4 - (4x + 5)/2 = 3/4

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Homework Help Overview

The discussion revolves around solving the equation (3x - 7)/4 - (4x + 5)/2 = 3/4, which falls under the subject area of algebra, specifically dealing with linear equations and rational expressions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's approach of eliminating denominators by multiplying both sides by 4, leading to a simplified equation. Some participants point out errors in distribution and question the validity of conclusions drawn from the resulting equations.

Discussion Status

There is an ongoing exploration of the mistakes made in the original calculations, with participants providing clarifications and corrections regarding the distribution of terms. Multiple interpretations of the steps taken are being examined, and while some guidance has been offered, there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are addressing potential misunderstandings in the manipulation of the equation, particularly regarding the handling of negative signs and the implications of reaching certain conclusions in algebraic reasoning.

Gringo123
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Can someone please tell me where I have gone wrong here? I have to solve the following equation:

(3x - 7)/4 - (4x + 5)/2 = 3/4

I attempted to do it by muliplying boths sides by 4 to get rid of the denominators, leaving me with:

3x - 7 - 8x + 10 = 3
simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.
 
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You have incorrectly distributed the minus 1 over the second term in brackets.
 
Hi Cyosis. Thanks for your reply. I'm afraid I don't understand. can you clarify your statement please?
Many thanks
 
Sure, -(4x+5)=-4x-5 \neq \underbrace{-4x+5}_\text{what you did}.
 
Gringo123 said:
...
simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.

Besides what Cyosis said, there's another problem here...

If you reach the conclusion that -5x = 0 in an arbitrary equation, there is nothing (necessarily) wrong with that. Just divide both sides by -5 and the result is that x = 0. "-5x = 0" is false for many values of x, but it is not ALWAYS false, as we have seen.

If you reach a conclusion that is ALWAYS false (e.g. " 1=2 "), then that is nonsense.

x = 0 would have been the solution, had you arrived at -5x = 0 in a correct way.
 
Gringo123 said:
Can someone please tell me where I have gone wrong here? I have to solve the following equation:

(3x - 7)/4 - (4x + 5)/2 = 3/4

I attempted to do it by muliplying boths sides by 4 to get rid of the denominators, leaving me with:

3x - 7 - 8x + 10 = 3
simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.

If you put it on a commen dinominator

like this \frac{(3x-7)-(8x+10)}{4} = \frac{3}{4} and multiply both sides by 4 and clean up the act you get

-5x -17 = 3 \Leftrightarrow -5x = 20 and thus the only x which solves the original eqn is x = -4.
 
Last edited:
Susanne217 said:
\frac{(3x-7)-(8x+10)}{4} = \frac{3}{4} and multiply both sides by 4 and clean up the act you get

-5x + 3 = 3 \LeftRightarrow -5x = 0

No, you did exactly the same mistake Gringo did. -7-(+10) is not 3.
 
Borek said:
No, you did exactly the same mistake Gringo did. -7-(+10) is not 3.

Its gringa, jefe ;)

and sorry its early here in my part of the Univers...
 

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