Solve Equation: 3x - 7/4 - (4x + 5)/2 = 3/4

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The equation 3x - 7/4 - (4x + 5)/2 = 3/4 was incorrectly simplified, leading to the conclusion that -5x = 0, which is misleading. The correct approach involves finding a common denominator, resulting in -5x - 17 = 3, which simplifies to x = -4. Missteps included improper distribution of the negative sign and arithmetic errors. Clarification was provided that reaching -5x = 0 is not inherently incorrect, but the method to arrive at that conclusion was flawed. The final solution to the equation is x = -4.
Gringo123
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Can someone please tell me where I have gone wrong here? I have to solve the following equation:

(3x - 7)/4 - (4x + 5)/2 = 3/4

I attempted to do it by muliplying boths sides by 4 to get rid of the denominators, leaving me with:

3x - 7 - 8x + 10 = 3
simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.
 
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You have incorrectly distributed the minus 1 over the second term in brackets.
 
Hi Cyosis. Thanks for your reply. I'm afraid I don't understand. can you clarify your statement please?
Many thanks
 
Sure, -(4x+5)=-4x-5 \neq \underbrace{-4x+5}_\text{what you did}.
 
Gringo123 said:
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simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.

Besides what Cyosis said, there's another problem here...

If you reach the conclusion that -5x = 0 in an arbitrary equation, there is nothing (necessarily) wrong with that. Just divide both sides by -5 and the result is that x = 0. "-5x = 0" is false for many values of x, but it is not ALWAYS false, as we have seen.

If you reach a conclusion that is ALWAYS false (e.g. " 1=2 "), then that is nonsense.

x = 0 would have been the solution, had you arrived at -5x = 0 in a correct way.
 
Gringo123 said:
Can someone please tell me where I have gone wrong here? I have to solve the following equation:

(3x - 7)/4 - (4x + 5)/2 = 3/4

I attempted to do it by muliplying boths sides by 4 to get rid of the denominators, leaving me with:

3x - 7 - 8x + 10 = 3
simplified: -5x + 3 = 3

which is clearly nonsense as that means -5x would equal 0.

If you put it on a commen dinominator

like this \frac{(3x-7)-(8x+10)}{4} = \frac{3}{4} and multiply both sides by 4 and clean up the act you get

-5x -17 = 3 \Leftrightarrow -5x = 20 and thus the only x which solves the original eqn is x = -4.
 
Last edited:
Susanne217 said:
\frac{(3x-7)-(8x+10)}{4} = \frac{3}{4} and multiply both sides by 4 and clean up the act you get

-5x + 3 = 3 \LeftRightarrow -5x = 0

No, you did exactly the same mistake Gringo did. -7-(+10) is not 3.
 
Borek said:
No, you did exactly the same mistake Gringo did. -7-(+10) is not 3.

Its gringa, jefe ;)

and sorry its early here in my part of the Univers...
 
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