The function f(t) is expressed using Heaviside functions as f(t) = 7H(t) + bH(t-5), with the goal of determining the value of b. The calculation shows that at t = 5, f(5) equals 15, leading to the equation 15 = 49 + 7b, which simplifies to b = -34/7. However, a key point raised is that the function cannot be represented as a combination of Heaviside steps without addressing its domain, which is limited to positive real numbers. It is suggested to redefine the function as f(x) = 7H(x) + 8H(x-5) to ensure it is valid across the intended intervals. The discussion emphasizes the importance of correctly specifying the function's domain when using Heaviside functions.