Solve F2 Components & Find Magnitudes U & V Axes

  • Thread starter Thread starter Kaura
  • Start date Start date
  • Tags Tags
    Magnitude Statics
Click For Summary
SUMMARY

The discussion focuses on resolving the force F2 into its components along the non-orthogonal u and v axes, specifically calculating the magnitudes of these components. The correct magnitude for F2 along the u axis is established as 130 N, while the magnitude along the v axis is determined to be 77.6 N using the sine rule. The participants clarify the angles involved, noting that the angle between F2 and the v axis is 75 degrees. The importance of significant figures in the final answers is emphasized, with a requirement to express results using three significant figures.

PREREQUISITES
  • Understanding of vector decomposition in non-orthogonal bases
  • Familiarity with basic trigonometric functions (sine and cosine)
  • Knowledge of significant figures in scientific calculations
  • Ability to apply the sine rule in physics problems
NEXT STEPS
  • Study vector decomposition techniques in non-orthogonal coordinate systems
  • Learn how to apply the sine rule in various physics contexts
  • Review significant figures and their importance in scientific reporting
  • Practice resolving forces into components using trigonometric functions
USEFUL FOR

Students in physics or engineering courses, particularly those dealing with vector analysis and force resolution, as well as educators looking for examples of non-orthogonal vector decomposition.

  • #31
Interesting. I was not viewing u and v as a non-orthogonal basis, but as simply two unrelated axes/directions. You are probably correct in your interpretation!
 
  • Like
Likes   Reactions: I like Serena
Physics news on Phys.org
  • #32
Doc Al said:
Interesting. I was not viewing u and v as a non-orthogonal basis, but as simply two unrelated axes/directions. You are probably correct in your interpretation!

When seen in the standard orthonormal basis, consider that we have to solve:
$$\binom{150\cos(165^\circ)}{150\sin(165^\circ)} = \mathbf F_2 = F_{2,u} \mathbf{\hat u} + F_{2,v} \mathbf{\hat v}
= F_{2,u} \binom{\cos(15^\circ)}{\sin(15^\circ)} + F_{2,v} \binom{0}{1}$$
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
8K