Solve Fermi-Dirac Integral: Get Help Now!

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    Fermi-dirac Integral
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SUMMARY

The discussion centers on solving the Fermi-Dirac integral, specifically addressing the approximation methods using Taylor's series. The integral's result is derived under the condition where the variable u exceeds the Fermi energy level (u_f). The approximation simplifies the expression 1 + (exp(u - u_f)/kT) to (exp(u - u_f)/kT), leading to the reciprocal term (exp-(u - u_f)/kT). This method clarifies the integral's behavior in the context of Fermi-Dirac statistics.

PREREQUISITES
  • Understanding of Fermi-Dirac statistics
  • Familiarity with Taylor series expansion
  • Knowledge of thermodynamic concepts, particularly temperature (kT)
  • Basic calculus skills for integral evaluation
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  • Study the derivation of the Fermi-Dirac integral in detail
  • Learn about the implications of Fermi energy (u_f) in statistical mechanics
  • Explore advanced approximation techniques in statistical physics
  • Investigate the role of temperature (kT) in quantum statistics
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Students and researchers in physics, particularly those focusing on statistical mechanics and quantum statistics, will benefit from this discussion.

arneet
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Thread closed due to being posted in two forum sections
i am completely lost. there is an integral in my textbook in fermi dirac statistics whose result is written directly and am not able to understand . it is
integral.PNG
.
on expansion by using the method of taylor's series the result should be
result.PNG

where u_f is such that function of u is zero for u greater than uf.
please reply as soon as possible. thanks.
 
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I think this should have been posted in physics thread. Anyways, i will explain here...Assume u is greater than uf...so (u-uf) is so large...
so in 1+(exp(u-uf)/kT) can be approximated as (exp(u-uf)/kT)

The reciprocal of this term is (exp-(u-uf)/kT).

Hope this helps
 
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Alpharup said:
I think this should have been posted in physics thread. Anyways, i will explain here...Assume u is greater than uf...so (u-uf) is so large...
so in 1+(exp(u-uf)/kT) can be approximated as (exp(u-uf)/kT)

The reciprocal of this term is (exp-(u-uf)/kT).

Hope this helps
thanks for replying,it helped.
 

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