Solve for a and b | Homework Help on Angles | 900 = a + b, a = b/14

[-Physician]

Homework Statement

This is the problem:
$a+b=$90⁰ (degrees)
$a=\frac{b}{14}$
Find a and b.

Homework Equations

$a+b=$90⁰ (degrees)
$a=\frac{b}{14}$

The Attempt at a Solution

$a+b=$90⁰
$(\frac{b}{14})+b=$90⁰
$\frac{b + 14b}{14} (14 and 14 get simplified)=$ 90⁰
$2b=$90⁰
$b=\frac{90}{2} =$45⁰

Now we have to find a .

$a=\frac{b}{14}=\frac{45}{14}=$3.214285714...(etc)⁰

Now we need to finish the equation :
$a+b=$90⁰=(3.214285714...+45)⁰= 48.214285714...⁰ ≠ 90⁰
I think my mistake is at $\frac{b+14b}{14}$, because b+14b/14 gives us 15b/14, but i am simplifying because that's the only way(for me) to get to the end.

 

[Dadface]

15b/14=90
Now multiply both sides by 14 and you get:
15b=90*14
To get b divide both sides by 15.

Try practising rearranging equations so you can do them quickly

 

[-Physician]

Oh, i knew the problem was there, so that would be :

$a+b=$90⁰
$a=\frac{b}{14}$
$\frac{b}{14} + b =$90⁰
$\frac{15b}{14}=$90⁰
$15b=90 * 14$
$15b=$1260⁰
$b=\frac{1260}{15}=$84⁰
$a=\frac{b}{14}=\frac{84}{14}=$6⁰
$a+b=$90⁰=(6+84)⁰=90⁰ right?

 

[Dadface]

Right.