Confirm a) & Solve b): Homework Help

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Homework Help Overview

The discussion revolves around confirming the correctness of a solution to part (a) of a problem involving complex numbers and exploring the next steps for part (b). The context appears to involve polar and rectangular forms of complex numbers and their roots.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster seeks confirmation of their solution for part (a) and expresses uncertainty about how to proceed with part (b). Some participants question the correctness of the original poster's approach and suggest that there may be a misunderstanding of the problem requirements.

Discussion Status

There is an active exchange of ideas, with some participants providing detailed insights into the correct method for finding the roots of complex numbers in polar form. However, there is no explicit consensus on the correctness of part (a) as the original poster's understanding is challenged.

Contextual Notes

Participants are discussing the implications of using polar versus rectangular forms for complex numbers, and there seems to be a focus on the importance of correctly interpreting the problem statement before proceeding with calculations.

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Homework Statement



http://img139.imageshack.us/img139/999/ksknl6.th.jpg http://g.imageshack.us/thpix.php

Could someone confirm that the a) part is correct, and if it is, then what is the next step? :)
And I am not exactly sure what to do in the b) part.

I would really appreciate if someone could help me out with this. :)

Thanks in advance.
 
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NO, (a) is not correct because you haven't answered the question! I think you have misunderstood what is asked. If you were asked to find [itex]^4\sqrt{16}[/itex], you wouldn't answer "161/4"!

Don't change from polar to rectangular form until after you have done the root! One important reason for using polar form for complex numbers is the fact that
[tex][r (cos(\theta)+ i sin(\theta)]^n= r^n(cos(n\theta)+ i sin(n\theta))[/tex]

For n= 1/4,
[tex](7(cos(\pi/2)+ i sin(\pi/2))^{1/4}= 7^{1/4}(cos(\pi/8)+ i sin(\pi/8))[/tex]
Also, since adding [itex]2\pi[/itex] to the argument doesn't change the complex number, and [itex]2\pi/4= \pi/2[/itex] another fourth root is
[tex]7^{1/4}(cos(\pi/4+ \pi/2)+ i sin(\pi/4+ \pi/2))[/tex]
yet another is
[tex]7^{1/4}(cos(\pi/4+ \pi)+ i sin(\pi/4+ \pi))[/tex]
and, finally,
[tex]7^{1/4}(coS(\pi/4+ 3\pi/2)+ i sin(\pi/4+ 3\pi/2))[/tex]

Those are the four fourth roots of [itex]7(cos(\pi/2)+ i sin(\pi/2))= 7i[/itex]
 
Edit: Shows what I know. Listen to HallsofIvy instead
 
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