Solve for Intensity: Easy Formula Manipulation for Finding Intensity

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Homework Help Overview

The discussion revolves around manipulating the formula for intensity in the context of sound or light intensity, represented by the equation B = 10log(I/Io). Participants are attempting to solve for the variable I.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are exploring different manipulations of the logarithmic equation to isolate I. There are attempts to rewrite the equation and questions about the correctness of their derived forms.

Discussion Status

Some participants have provided guidance on how to rearrange the equation, while others express confusion about their calculations. There is a recognition of the complexity involved in the manipulation of logarithmic functions.

Contextual Notes

Some participants mention potential issues with the values used for Io and B, indicating that these may affect the outcome of their calculations.

Sucks@Physics
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I'm trying to find the intensity of something. I know the equation is

B = 10log(I/Io)

But how to I solve for I? What would the equation be? For some reason I can't make it work.
 
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logarithms

Does this help?
If a = log(b)

then b = 10^a
 
No, i still can't ge thte correct equation, i come up with something like (10x10^B)/Io
 
Rewrite the equation as
I/I0 = 10^(B/10)
 
Last edited by a moderator:
Sucks@Physics said:
No, i still can't ge thte correct equation, i come up with something like (10x10^B)/Io

Not quite:
B = 10log(I/Io)
B/10 = log(I/Io)
10^(B/10) = I/Io
I = Io*10^(B/10)
 
Thanks, that is kinda tricky, but now i understand it
 
From the provided information, Doc Al's equation is correct. You may be using wrong values for your Io and B, or your intensity equation could be incorrect.
 

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