MHB Solve for the Two Numbers: Sum 9, Difference 6

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To solve for the two numbers with a sum of 9 and a difference of 6, let x be the smaller number and express the larger number as x + 6. Setting up the equations, x + (x + 6) = 9 simplifies to 2x + 6 = 9. Solving this gives x = 1. Therefore, the two numbers are 1 and 8.
paulmdrdo1
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can you help me solve this just using one variable

the sum of two numbers is 9 and their difference is 6. what are the numbers?

thanks!
 
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paulmdrdo said:
the sum of two numbers is 9 and their difference is 6. what are the numbers?
Let $x$ be the smaller of the two numbers. Since the difference is 6, the other number is $x+6$. Now try writing the equation saying that the sum of these numbers is 9 and try solving it.
 
Alternatively:

$x + y = 9$
$x - y = 6$

The second equation tells us:

$x = y + 6$

So substitute that value for $x$ into the first equation, to get an equation in the single variable $y$.
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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