Solve for x: f(g(x))=30 | Factor & Simplify: (x+5)^2+6(x+5)(x-4)

  • Thread starter Thread starter Nikola Tesla
  • Start date Start date
Click For Summary

Homework Help Overview

The original poster presents two problems: the first involves solving for x in the equation f(g(x))=30, where f(x)=x^2-3x and g(x)=√(x+6). The second problem requires factoring and simplifying the expression (x+5)^2 + 6(x+5)(x-4).

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the transformation of the first equation into a quadratic form and suggest making a substitution to simplify the problem. There is uncertainty about the next steps after reaching a specific equation. For the second problem, one participant suggests factoring out (x + 5) and provides a partial factorization.

Discussion Status

Participants are actively engaging with both problems, exploring different approaches and transformations. Some guidance has been offered regarding substitutions and factoring, but there is no explicit consensus on the next steps or final outcomes.

Contextual Notes

There is a noted uncertainty in the first problem regarding how to proceed after simplifying the equation. The second problem involves a request for simplification and factoring, indicating a focus on algebraic manipulation.

Nikola Tesla
Messages
11
Reaction score
0
If f(x)=x^2-3x and g(x)=in square root of x+6, solve for x if f(g{x))=30

Also, factor this expression and simplify if necessary: (x+5)^2+6(x+5)(x-4)

Thanks.
 
Physics news on Phys.org
What have you tried so far? What are you having trouble with?
 
For the first one, I got to, x+6 - 3(square root of x+6) = 30 lol

I don't know what to do next, I think I'm supposed to get rid of the three, but I'm not sure how.
 
Nikola Tesla said:
For the first one, I got to, x+6 - 3(square root of x+6) = 30 lol

I don't know what to do next, I think I'm supposed to get rid of the three, but I'm not sure how.

You can make a substitution to end up with a quadratic equation,

let u = square root of (x+6)

so you end up with

u2 - 3u = 30

You can then solve for u and thn substitue back to solve for x.
 
Nikola Tesla said:
Also, factor this expression and simplify if necessary: (x+5)^2+6(x+5)(x-4)
For the second one, you may want to factor (x + 5) out.
(x + 5)2 + 6(x + 5)(x - 4) = (x + 5) (x + 5 + 6(x - 4)) = ...
Can you go from here? :)
 

Similar threads

Replies
3
Views
3K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
19
Views
3K