Solve for x(t) and v(t) given a Force equation using Mathematica

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The discussion focuses on solving a second-order nonlinear differential equation derived from the force equation F = ma. The user expresses confusion about integrating the equation and how to apply Mathematica for the solution. Key insights include using the chain rule to relate acceleration to velocity and position, leading to the equation v dv = (F/m) dx. The user has made progress on the first part of the problem but seeks guidance on implementing the solution in Mathematica. Overall, the conversation emphasizes the integration of force equations and the application of calculus principles.
zeesyk
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Homework Statement

Homework Equations


F= ma or F= md^2x/dt^2

The Attempt at a Solution


I know that this second order differential is non linear. I attempted to solve the problem as -k/x^2 = md^2x/dt^2 but I'm getting trouble since it is a second order ODE and I haven't learned how to solve those yet. I was also looking at my class notes to a similar problem but my professor included potential energy? I'm a bit confused. Any help would be greatly appreciated. If you can also show me how to solve this on Mathematica, that would also be a plus. I don't have any experience with it.
 

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update: i think i may have solved the first part? Now I need to figure out to put in on Mathematica.
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You need to use the chain rule from calculus.

You know that a = dv/dt.

However, this can also be written as a = (dv/dx) * (dx/dt) = v (dv/dx).

This means that your force equation a = F/m can now be written as

v \frac{dv}{dx} = \frac{F}{m}

Consequently, what you need to solve (or integrate) is

v dv = \frac{F}{m} dx

since F is given as a function of x.

Zz.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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