Solve Garden Hose Problem: 19.6s to Fill 24L Container

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Homework Help Overview

The discussion revolves around a problem involving fluid dynamics, specifically the use of a garden hose to fill a 24-liter container. Participants are analyzing the relationship between flow rate, area, and time required to fill the container, while addressing unit conversions and formula applications.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply the formula for flow rate and questioning the correctness of unit conversions and area calculations. There are discussions about dimensional analysis and the correct formula for the area of a circle.

Discussion Status

Several participants have pointed out potential errors in unit conversions and calculations. There is an ongoing exploration of the correct formulas and approaches to solve the problem, with some participants expressing a need for clarification and assistance in understanding the concepts involved.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the type of assistance they can receive. There is a noted emphasis on ensuring correct unit conversions and understanding the underlying physics principles.

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Homework Statement


A garden hose is used to fill a large metal container which can hold 24.0 L of liquid. If the radius of the garden hose's nozzle is 1.2 cm, and the speed of the water at this point is 272.0 cm/s, how long (in seconds) would it take to fill the container with water, assuming that none of it splashes out?
Hint: Use the fact that 1 L = 1000 cm3

Placing all relevant data in SI;
24L = 24,000cm3
= 0.024m3

V = 272cm/s
= 2.72 m/s

Homework Equations



ΔV/Δt = Av
Δt = ΔV/Av

The Attempt at a Solution



ΔV(metal container) = 0.024m 3
Δt = ?
A(nozzle) = ∏(0.012)2 = 0.00045m2
v(water) = 2.72m/s

Δt = ΔV/Av
Δt = 0.024/(0.00045)*(2.72)
Δt = 19.6s

Now that I've figured it out, I suppose this doesn't really belong in advanced physics - even though it is part of my undergraduate.
 
Last edited:
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How many centimeters in 1 meter?

24L = 24000 cm^3 (OK)
24L = 24 M^3 (?)

272 cm/s = .272m/s (?!)

What is the formula for the area of a circle given the radius?

(Hint: it's not 2 pi r)
 
Check your units and formulas, you got some major mistakes in there. This question is easy and mistake proof if you use dimensional anaylsis.
 
Vadar2012 said:
Check your units and formulas, you got some major mistakes in there.
I am aware I have some major mistakes, which is why I posted it. I need help getting started, I only posted what I had to show I made an attempt.

Edit: Oh I see what you are talking about, yes. This is rather embarrassing. Never trust a friend with conversions...
 
SteamKing said:
How many centimeters in 1 meter?

24L = 24000 cm^3 (OK)
24L = 24 M^3 (?)

272 cm/s = .272m/s (?!)

What is the formula for the area of a circle given the radius?

(Hint: it's not 2 pi r)
I fixed up the silly mistakes, it is 1:00am and I've been reviewing for nearly 14 hours now. I just need help finding the correct formulas for solving this problem.
 
You still have a major problem:

24L = 24000 cm^3 OK

24L = 240 m^3 (?!)

I trust you know that if I have a cube which measures 10 cm on each side, the volume of the cube is 10 cm * 10 cm * 10 cm = 1000 cm^3 = 1.0 L
 
SteamKing said:
You still have a major problem:

24L = 24000 cm^3 OK

24L = 240 m^3 (?!)

I trust you know that if I have a cube which measures 10 cm on each side, the volume of the cube is 10 cm * 10 cm * 10 cm = 1000 cm^3 = 1.0 L
As stated, it's 1:00am :bugeye:
Thanks for pointing that out, any idea where I can start to look for the correct equation? I looked at continuity (as suggested), but I am getting a massive amount of time for that.

Edit: I think I figured it out, it was entirely conversions that threw me off. Wow, how embarrassing.I posted my final answer.
 
Last edited:

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