Calculating Fill Time for Inflatable Pool Using Garden Hose

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Homework Help Overview

The discussion revolves around calculating the time required to fill a child's inflatable wading pool using a garden hose. The problem involves concepts from fluid dynamics, specifically related to flow rates and volume calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the volume of the pool and the flow rate from the hose but expresses uncertainty about the equations needed to relate these quantities to time. Some participants question the accuracy of the volume and area calculations, suggesting that density is necessary for converting mass to volume.

Discussion Status

Participants are actively engaging with the problem, with some providing corrections and guidance on the calculations. There is a recognition of mistakes in initial calculations, and the original poster indicates progress in understanding the flow rates. However, there is no explicit consensus on the final approach or solution.

Contextual Notes

There is mention of constraints regarding the knowledge of density, as it has not been covered in the original poster's class yet, which may affect the discussion on volumetric flow rates.

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Homework Statement



To fill a child's inflatable wading pool you use a garden hose with a diameter of 2.8 cm. Water flows from this hose with a speed of 1.1 m/s. How long will it take to fill the pool to a depth of 32 cm if it is circular and has a diameter of 2.7 m?

Homework Equations


delta m=p1 A1 v1 delta t
(p=density, A=area, v=velocity, t=time)

A1 v1=A2 v2

Q=A v

idk if there is another equation that deals with time, i can't find any.

The Attempt at a Solution


since everything is dealing with water, i didn't really consider density.

the amount of water needed:
V= pi r^2 h=pi (1.35)^2 (.32)= 1.83 m^3

the area of the hose is:
A= pi r^2= pi (.014)^2= 6.16e-4 m^2

Q=A v=6.16e-4 (1.1)=6.78e-4 m^3/s

mass flow rate= .6776 kg/s

i don't really know where to go from here...
 
Last edited:
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first, your volume of pool measurement is a little wrong. You've used the diameter as a radius in your equqtion.
You've also made the sam mistake in calculating the cross sectional area of the hose.
delta m over delta t will give you your mass flow rate. But you need your volumetric flow rate. so how do you turn mass in a volume (hint: pensity is required)

keep trying and le tme know.
 
my typing is terrible this morning, sorry for the spelling mistakes. going to get some more coffee :smile:
 
redargon said:
first, your volume of pool measurement is a little wrong. You've used the diameter as a radius in your equqtion.
You've also made the sam mistake in calculating the cross sectional area of the hose.
delta m over delta t will give you your mass flow rate. But you need your volumetric flow rate. so how do you turn mass in a volume (hint: pensity is required)

keep trying and le tme know.

i fixed the problems and hopefully they are right. i found the mass flow rate and also the volumetric flow rate. we haven't learned about pensity in our class yet...so there has to be a different way.
 
i figured it out. thanks :)
 
pensity was a spelling mistake for density, sorry. Glad you got it, no prob.
 

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