Solve IVP 2nd order differential equation

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SUMMARY

The discussion focuses on solving the initial value problem (IVP) for the second-order linear homogeneous differential equation: y'' - 2y' + 2y = 0. The particular solutions provided are y1 = (e^x)*(cos x) and y2 = (e^x)*(sin x). To find the specific solution that satisfies the initial conditions y(0) = 0 and y'(0) = 5, one must express the general solution as y = A y1 + B y2 and then substitute the initial conditions to solve for the constants A and B.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with linear combinations of functions
  • Knowledge of initial value problems (IVP)
  • Basic calculus, particularly differentiation
NEXT STEPS
  • Study the method of undetermined coefficients for solving differential equations
  • Learn about the Wronskian and its role in determining linear independence of solutions
  • Explore the application of Laplace transforms in solving IVPs
  • Investigate the characteristics of homogeneous vs. non-homogeneous differential equations
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Students studying differential equations, mathematicians, and engineers looking to solve initial value problems in applied mathematics.

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Homework Statement


Find the particular solution of the linear, homogeneous, 2nd order differential equation: y'' - 2y' + 2y = 0, given the solutions y1 = (e^x)*(cos x), y2 = (e^x)*(sin x), y(0) = 0, y'(0) = 5.


Homework Equations





The Attempt at a Solution


How do I begin? I'd really appreciate any help! Thank you.
 
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Your general solution (before applying initial conditions) is a general linear combination of your two given solutions:
y = A y1 + B y2.
You then substitute in your two initial conditions and solve for the arbitrary constants A and B.
 
Ah, thank you for putting it so short and clearly :)
 

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