Solve IVP 2nd order differential equation

In summary, to find the particular solution of the given differential equation, you can use the general linear combination of the two given solutions, y = A y1 + B y2, and then substitute in the initial conditions to solve for the arbitrary constants A and B.
  • #1
accountkiller
121
0

Homework Statement


Find the particular solution of the linear, homogeneous, 2nd order differential equation: y'' - 2y' + 2y = 0, given the solutions y1 = (e^x)*(cos x), y2 = (e^x)*(sin x), y(0) = 0, y'(0) = 5.


Homework Equations





The Attempt at a Solution


How do I begin? I'd really appreciate any help! Thank you.
 
Physics news on Phys.org
  • #2
Your general solution (before applying initial conditions) is a general linear combination of your two given solutions:
y = A y1 + B y2.
You then substitute in your two initial conditions and solve for the arbitrary constants A and B.
 
  • #3
Ah, thank you for putting it so short and clearly :)
 

FAQ: Solve IVP 2nd order differential equation

What is an initial value problem (IVP) for a 2nd order differential equation?

An initial value problem for a 2nd order differential equation is a mathematical equation that involves a function, its derivatives, and initial conditions, typically given as the value of the function and its first derivative at a specific point. The goal is to find a solution to the differential equation that satisfies the given initial conditions.

What is the general form of a 2nd order differential equation?

The general form of a 2nd order differential equation is y'' + p(x)y' + q(x)y = g(x), where y is the unknown function, x is the independent variable, p(x) and q(x) are known functions, and g(x) is a known function. This form can also be written as y'' = f(x, y, y').

How do you solve a 2nd order differential equation using an initial value problem?

To solve a 2nd order differential equation using an initial value problem, you first need to express the equation in standard form, with all terms on one side and the unknown function and its derivatives on the other side. Then, you can use various techniques such as separation of variables, substitution, or the method of undetermined coefficients to find a general solution. Finally, you can use the given initial conditions to determine the specific solution that satisfies the initial value problem.

What are the different methods for solving a 2nd order differential equation?

There are several methods for solving a 2nd order differential equation, including separation of variables, substitution, the method of undetermined coefficients, and the method of variation of parameters. Each method has its own advantages and is suitable for different types of equations.

Can a 2nd order differential equation have more than one solution?

Yes, a 2nd order differential equation can have more than one solution. This is because the general solution to a 2nd order differential equation contains two arbitrary constants, which can take on different values depending on the given initial conditions. Therefore, each set of initial conditions can lead to a different solution to the same differential equation.

Back
Top