Solve Kinematics Problem: 3x Max Height, Find Angle

[Johnny Blade]

What is the angle if the reach is three (3) times the maximum height.

I put both of the reach and max height formula together to isolate theta

p=\frac{V_{0}^{2}sin(2\theta)}{-g} and h_{max}=\frac{V_{0}^{2}sin^{2}\theta}{-2g}

At the end it gave me this:

\frac{3sin\theta}{2}=2cos\theta

Am I getting rusty on my trigonometry? How would you solve this?

 

[Andy_ToK]

What is the angle if the reach is three (3) times the maximum height.

I put both of the reach and max height formula together to isolate theta

p=\frac{V_{0}^{2}sin(2\theta)}{-g} and h_{max}=\frac{V_{0}^{2}sin^{2}\theta}{-2g}

At the end it gave me this:

\frac{3sin\theta}{2}=2cos\theta

Am I getting rusty on my trigonometry? How would you solve this?

your solution was right, all u have to do then is to plug it into your calculator and calculate arctan4/3

 

[Johnny Blade]

I see it. Thank you very much.