# Solve Kinematics Problem: Initial Velocity of Jogger

• Ksenia
In summary, the problem presents a jogger who accelerates constantly to a velocity of +2.3m/s in 6.5s, and then stops after jogging 11m. The question is: what was the initial velocity of the jogger? There are no given answers, and the wording may be confusing. However, using the kinematics formulae v = v_0 + (a)(t) and d = d_0 + v_0 t + (1/2)(a)(t^2), we can solve for the initial velocity by setting d = 11m and t = 6.5s.

#### Ksenia

Okay so I have tried for hours to figure this out and can't. Please show me how to get the answers; what do I already have, what do I need, and what kinematics formula(s) do I use? Thanky ou so much!
Problem:
A jogger accelerates constantly to a velocity of +2.3m/s in 6.5s. After jogging 11m, the jogger stops. What was the initial velocity of the jogger?
I can use any rearrangement of the 5 kinematics formulas (each one only has 4 variables) to solve this question.
I do not understand if the final velocity is 0m/s or 2.3m/s. And does the 11m come after he accelerates or is the 11m the total distance that was traveled?

Ksenia said:
I do not understand if the final velocity is 0m/s or 2.3m/s. And does the 11m come after he accelerates or is the 11m the total distance that was traveled?

I can't interpret the problem either. Did you quote it exactly?

Ksenia said:
A jogger accelerates constantly to a velocity of +2.3m/s in 6.5s. After jogging 11m, the jogger stops. What was the initial velocity of the jogger?
Hi Ksenia. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]

We could recast this data into a legitimate kinematics question. But I would like to see the original wording just the same.

Do you know what answer they are looking for?

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Stephen Tashi said:
I can't interpret the problem either. Did you quote it exactly?
Yes I worded it just like it was in the problem. And no there are no answers as this came from my correspondence module
:(

NascentOxygen said:
Hi Ksenia. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]

We could recast this data into a legitimate kinematics question. But I would like to see the original wording just the same.

Do you know what answer they are looking for?
No, the answer isn't given and the wording is exactly as in my booklet.

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Why not, as a start, work out how far the jogger would travel if they started from rest and accelerated as described.

Ksenia said:
Yes I worded it just like it was in the problem. And no there are no answers as this came from my correspondence module
:(

My guess is that "After jogging 11m, the jogger stops" is a badly written sentence that should have been worded to convey the idea that during the time the jogger is accelerating he travels 11 meters. So he "stops accelerating" not "stops moving".

If you following the template for homework, you will state the 5 kinematic equations. My guess is that your are expected to work with $v = v_0 + (a)(t)$ and $d = d0 + v_0 t + (1/2)(a)(t^2)$ where we take $d_0 = 0$ as the distance where the jogger began accelerating.