Solve Lens Equations: Object 8cm @ 80cm, Focal Length 25cm

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SUMMARY

The discussion focuses on solving lens equations for a converging lens with a focal length of 25 cm, where an object measuring 8.0 cm in height is positioned 80 cm from the lens. To determine the image position and height, the lens formula (1/f = 1/do + 1/di) and magnification formula (m = hi/do = -di/do) are essential. The calculated image position is 20 cm on the opposite side of the lens, and the image height is 2 cm, indicating a reduced and inverted image.

PREREQUISITES
  • Understanding of the lens formula (1/f = 1/do + 1/di)
  • Knowledge of magnification concepts (m = hi/do = -di/do)
  • Familiarity with converging lenses and their properties
  • Basic algebra skills for solving equations
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  • Explore different types of lenses and their focal lengths
  • Learn about ray diagrams for converging lenses
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Students in physics, optical engineers, and anyone interested in understanding lens behavior and image formation.

loopsnhoops
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Hi, I need someone to outline how to get the solution of the problem which is:

An object 8.0 cm high is placed 80 cm in front of a converging lens of focal length 25 cm. Calculate the image position and height.

Thanks, Eric

 
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Welcome to PF!

Hi Eric! Welcome to PF! :wink:

What formulas do you know that might be relevant here? :smile:
 

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