- #1

fk378

- 367

- 0

## Homework Statement

Determine whether the sequence converges or diverges. If it converges, what does it converge to?

(cos[n])^2 / (2^n)

## Homework Equations

L'Hospital's Rule

or

Squeeze Theorem

## The Attempt at a Solution

As n-->infinity, this function approaches infinity/infinity. Applying L'Hospital's rule gives -(sin[n])^2 / 2 which gives infinity/2=infinity.

However, if I use the squeeze theorem to say that 0<(cos[n])^2<1 and then divide everything by 2^n, then I can say that this function approaches 0.

Which is the correct method?