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scientifico
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Homework Statement
3^{x} + 3^{x+1} = 4^{x}
Can I do this ?
Log 3^{x} + Log 3^{x+1} = Log4^{x}
thanks
scientifico said:Homework Statement
3^{x} + 3^{x+1} = 4^{x}
Can I do this ?
Log 3^{x} + Log 3^{x+1} = Log4^{x}
thanks
scientifico said:Can I do this ?
Log 3^{x} + Log 3^{x+1} = Log4^{x}
scientifico said:How can I solve my equation ?
scientifico said:3(1-3^x) < 5^x(1-3^x)
must I impose 1-3^x > 0 and 1-3^x < 0 ?
A logarithm equation is an equation that involves the use of logarithms. Logarithms are mathematical functions that are the inverse of exponential functions. They are used to solve for unknown variables that are in the exponent.
To solve a logarithm equation, you need to isolate the logarithm term on one side of the equation and the non-logarithmic terms on the other side. Then, you can use the properties of logarithms to simplify the equation and solve for the unknown variable.
The properties of logarithms include the product property, quotient property, power property, and change of base property. These properties allow us to manipulate logarithmic expressions and equations to make them easier to solve.
For example, let's say we have the equation log_{2}(x+3) = 2. To solve this, we can rewrite it using the power property as 2^{2} = x+3. Then, we can subtract 3 from both sides to get x = 1. Therefore, the solution to the equation is x = 1.
You can check your solution by plugging it back into the original equation. If it satisfies the equation, then it is the correct solution. In our previous example, we can plug in x = 1 to get log_{2}(1+3) = 2, which simplifies to 2 = 2, showing that our solution is correct.