Solve Logarithm Problem: "log3m4, in terms of n

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Homework Help Overview

The discussion revolves around the logarithmic expression "log3m4" and its relation to "log3m = n". Participants are attempting to express log3m4 in terms of n, exploring the properties of logarithms and their definitions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion about setting up the equation and the meaning of "in terms of n". There are attempts to relate log3m4 to log3m, with some questioning the application of logarithmic rules. Others explore the implications of exponential forms and how they relate to the original logarithmic expressions.

Discussion Status

There is an ongoing exploration of the relationship between the logarithmic and exponential forms. Some participants are questioning their understanding of logarithmic properties, while others are attempting to clarify these concepts. Guidance has been offered regarding the manipulation of exponents, but no consensus has been reached on the correct approach.

Contextual Notes

Participants note that they have not yet covered logarithmic rules in their coursework, which may be impacting their ability to solve the problem effectively. The problem is part of an "Extend" section, indicating a focus on deeper understanding rather than straightforward application.

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Homework Statement



"If log3m = n, then determine log3m4, in terms of n."

2. The attempt at a solution

I'm pretty much clueless as how to set up the equation, and what 'in terms of n' means. My guess is log3m = log3m4, but I'm confused about what to do next. The answer in the textbook says 4n, and this leads me to believe that you take out the exponent from log3m4 but I'm not sure how you would do this.

Thanks.
 
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Aokei said:

Homework Statement



"If log3m = n, then determine log3m4, in terms of n."

2. The attempt at a solution

I'm pretty much clueless as how to set up the equation, and what 'in terms of n' means. My guess is log3m = log3m4, but I'm confused about what to do next. The answer in the textbook says 4n, and this leads me to believe that you take out the exponent from log3m4 but I'm not sure how you would do this.

Thanks.

Weren't you given some rules of logarithms like log(a^b)=b*log(a)?
 
Dick said:
Weren't you given some rules of logarithms like log(a^b)=b*log(a)?

Nope, my class was only told exponential form and logarithmic form, no rules of logarithms so far. We're only on the first part of the logarithm unit, the question above is a part of the "Extend" section of the chapter, which thought provoking questions than the others.
 
Aokei said:
Nope, my class was only told exponential form and logarithmic form, no rules of logarithms so far. We're only on the first part of the logarithm unit, the question above is a part of the "Extend" section of the chapter, which thought provoking questions than the others.

Ok, that's fair. So log_3 m=n means 3^n=m. So m^4=(3^n)^4. What does the exponential form tell you about that?
 
Dick said:
Ok, that's fair. So log_3 m=n means 3^n=m. So m^4=(3^n)^4. What does the exponential form tell you about that?

So log_3 m=n means 3^n=m.

- I understand this part.

m^4=(3^n)^4

- this confuses me a bit, since there's a fourth power on both sides.

I thought log_3 m^4 = n was: 3^n = m^4.
 
Aokei said:
So log_3 m=n means 3^n=m.

- I understand this part.

m^4=(3^n)^4

- this confuses me a bit, since there's a fourth power on both sides.

I thought log_3 m^4 = n was: 3^n = m^4.

That's a good start. But I'm having a hard time understanding the problem on the second. If a=b then a^4=b^4, yes?
 
Dick said:
That's a good start. But I'm having a hard time understanding the problem on the second. If a=b then a^4=b^4, yes?

I'm having trouble understanding the exponent part.

In this situation a≠b. Adding the forth power to (3^n) changes the equation. Maybe if I rewrite log_3 m^4 as log_3(m^4) might help. I'm confused as to how you move the exponent. The way I think of it is, the exponent moves with the variable m.

Sorry if you're having trouble understanding my problem :x.
 
Aokei said:
I'm having trouble understanding the exponent part.

In this situation a≠b. Adding the forth power to (3^n) changes the equation. Maybe if I rewrite log_3 m^4 as log_3(m^4) might help. I'm confused as to how you move the exponent. The way I think of it is, the exponent moves with the variable m.

Sorry if you're having trouble understanding my problem :x.

You are having some serious conceptual problems here. You've already agreed that 3^n=m. How can it not be that (3^n)^4=m^4? This part isn't about logs.
 
Dick said:
You are having some serious conceptual problems here. You've already agreed that 3^n=m. How can it not be that (3^n)^4=m^4? This part isn't about logs.

Since I'm having serious conceptual problems, can you show me the process to get the correct answer? The answer in the textbook is 4n.
 
  • #10
Aokei said:
Since I'm having serious conceptual problems, can you show me the process to get the correct answer? The answer in the textbook is 4n.

m^4=(3^n)*(3^n)*(3^n)*(3^n)=3^(4n). What's log_3 of m^4? I don't know how else to explain this.
 
  • #11
Dick said:
m^4=(3^n)*(3^n)*(3^n)*(3^n)=3^(4n). What's log_3 of m^4? I don't know how else to explain this.

Mkay, thank you for the aid, I'll see how it is tomorrow.
 
  • #12
Aokei said:
Mkay, thank you for the aid, I'll see how it is tomorrow.

Sure, just think it over. It's not that strange.
 

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