Solve Magnetic Problem: Charge Q w/ Vector Force of B=0.25T

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Homework Statement



the charge of Q= 1.6 uC is moving along the line x=y with speed v= 4.0*10^5 m/s. What is the vecotr force it experiences due to the magnetic field B= Boz, where Bo = 0.25T?

Homework Equations





The Attempt at a Solution



i know Fb must be perpendicular to B and B is on the z axis. but i don't know what should i do afterwards. please help.
 
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You just need to use the Lorentz force.

[tex]\vec{F}=q(\vec{E}+\vec{v}\times\vec{B})[/tex]

Remember, [itex]\vec{E}[/itex] and [itex]\vec{B}[/itex] are the fields not produced by charge [itex]q[/itex].