Solve Magnetic Problem: Charge Q w/ Vector Force of B=0.25T

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SUMMARY

The discussion centers on calculating the magnetic force experienced by a charge Q of 1.6 µC moving at a velocity of 4.0 x 105 m/s in a magnetic field B of 0.25 T directed along the z-axis. Participants emphasize the application of the Lorentz force equation, F = q(E + v × B), noting that the magnetic force is perpendicular to both the velocity and the magnetic field. The key takeaway is the necessity to understand the vector cross product in this context to determine the resultant force.

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  • Basic principles of electromagnetism
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Homework Statement



the charge of Q= 1.6 uC is moving along the line x=y with speed v= 4.0*10^5 m/s. What is the vecotr force it experiences due to the magnetic field B= Boz, where Bo = 0.25T?

Homework Equations





The Attempt at a Solution



i know Fb must be perpendicular to B and B is on the z axis. but i don't know what should i do afterwards. please help.
 
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You just need to use the Lorentz force.

[tex]\vec{F}=q(\vec{E}+\vec{v}\times\vec{B})[/tex]

Remember, [itex]\vec{E}[/itex] and [itex]\vec{B}[/itex] are the fields not produced by charge [itex]q[/itex].
 

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