Solve Math Word Problem: Bickford & Shawn Speed & Times

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Homework Help Overview

The problem involves determining the speeds and travel times of two individuals, Bickford and Shawn, based on their respective distances and the relationship between their speeds. The context is rooted in algebraic reasoning and the application of distance, rate, and time formulas.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up equations based on the relationship between the speeds of Bickford and Shawn, with Bickford traveling twice as fast as Shawn. There are attempts to clarify the variables and the equations derived from the problem statement.

Discussion Status

The discussion includes various attempts to establish the correct equations using the distance formula. Some participants seek clarification on the setup and the meaning of the variables involved, while others provide guidance on how to formulate the equations based on the given information.

Contextual Notes

There is an emphasis on understanding the relationships between the variables, and participants are navigating through the setup of the problem without providing explicit solutions.

bushman91
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Bickford traveled twice as fast as Shawn traveled. Thus, Bickford could travel the 320 miles to the reef in only 2 hours less than it took shawn to travel the 240-miles to Jane's house. Find the rates and times of both boys.

Just having problems figuring out the formula and how to set it up.

So Shawn is x
Which would make Bickford 2x
 
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Use d = rt. So for Bickford, 320 = 2v(t-2) and for Shawn 240 = vt.
 
Last edited:
Please explain how you set that up and the what the variables represent
 
Distance is defined as speed \times time . Let v be the speed of Shawn. Then 2v is the speed of Bickford. Also, let t be the time it takes Shawn to travel to Jane's house. Using the equation d = vt (where v is the speed) we can set up two equations with two unknowns.

Bickford's speed is 2v and his time is t-2 (two hours less time than Shawn) and he travels 320 miles. So we have 320 = 2v(t-2).

Shawn's speed is v and his time is t and he travels 240 miles. So we have 240 = vt. Can you solve for v and t?
 
thanks for the help, I should be able to get it now
 

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