Solve Matrices Problem: Find ab & c

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Homework Help Overview

The problem involves finding the values of variables a, b, and c in the context of matrix equations, specifically involving transposes and matrix multiplication. The equation given is ATCT + (CA)T = B, with specified matrices A, B, and C.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss manipulating the original equation and consider different forms of the matrices involved. There is an exploration of setting up a system of equations based on the matrix equality.

Discussion Status

Some participants have suggested alternative representations of the matrices and questioned the setup of the variables. There is an acknowledgment of potential issues with the original matrix definitions and the implications for finding a solution. One participant reports success after adjusting their approach based on feedback.

Contextual Notes

There is a concern regarding the constraints of the problem, particularly the requirement to input specific values for a, b, and c in a web-based assignment format. The discussion also touches on the implications of changing matrix elements on the overall problem context.

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Homework Statement



If ATCT+(CA)T=B where:

A=a c b a B = −34 44 −12 18 C = −3 −1 2 1

then what are the values of ab and c?

(These are all two by two matrices, I don't know how to format them on here. The T's are transposes.

The Attempt at a Solution



So I've tried a few times now with no success. As far as I'm aware ATCT+(CA)T=B is equivalent to 2ATCT, but I've tried doing them separately as well with no success. So I get it down to a bunch of a's and c's of b's to be equal to the B matrix. Then (I don't know if I'm actually allowed to do this) I match them with the corresponding values in the B matrix on the other side of the equation. This gives me a system of equations, which I change to an augmented matrix. I can then get it to RRE form, with the exception of a 4th row (only 3 variables?) which always ends up being something = 0, which throws me off.

Any help/suggestions?
 
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You can also write the equation as 2(CA)^T=B. If you transpose both sides, that's 2CA=B^T. C is invertible, so just solve for A. I get a matrix for A that doesn't have the two diagonal elements equal. That's probably why you are having problems solving the linear equations. Try it setting A=[[a,b],[c,d]] with 4 variables.
 
Sorry I'm not sure if I follow. So you're getting the same thing as me, where A is 4x3? How do I 'set' A to be four variables as opposed to 3?
 
DanielJackins said:
Sorry I'm not sure if I follow. So you're getting the same thing as me, where A is 4x3? How do I 'set' A to be four variables as opposed to 3?

All the matrices are 2x2. If I read your notation right A=a c b a mean A is a matrix with first row 'a c' and second row 'b a', right? There is no solution to your problem of that form because of the two 'a's in it. Change one of the 'a's to 'd' for example. Now you have four unknowns instead of three. Now there is a solution.
 
Won't that change the context of the question though?
 
DanielJackins said:
Won't that change the context of the question though?

Yes, it will. If you don't change the context then the answer is that there is no solution. Show that with your linear equations.
 
Problem is I can't, it's a web-based assignment and it expects me to input values for a, b, and c
 
Nevermind, I tried what you said and it worked out perfectly. Thanks a bunch!
 

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