Solve Matrices Problem: Find ab & c

  • Thread starter Thread starter DanielJackins
  • Start date Start date
  • Tags Tags
    Matrices
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 2K views
DanielJackins
Messages
39
Reaction score
0

Homework Statement



If ATCT+(CA)T=B where:

A=a c b a B = −34 44 −12 18 C = −3 −1 2 1

then what are the values of ab and c?

(These are all two by two matrices, I don't know how to format them on here. The T's are transposes.

The Attempt at a Solution



So I've tried a few times now with no success. As far as I'm aware ATCT+(CA)T=B is equivalent to 2ATCT, but I've tried doing them separately as well with no success. So I get it down to a bunch of a's and c's of b's to be equal to the B matrix. Then (I don't know if I'm actually allowed to do this) I match them with the corresponding values in the B matrix on the other side of the equation. This gives me a system of equations, which I change to an augmented matrix. I can then get it to RRE form, with the exception of a 4th row (only 3 variables?) which always ends up being something = 0, which throws me off.

Any help/suggestions?
 
Physics news on Phys.org
You can also write the equation as 2(CA)^T=B. If you transpose both sides, that's 2CA=B^T. C is invertible, so just solve for A. I get a matrix for A that doesn't have the two diagonal elements equal. That's probably why you are having problems solving the linear equations. Try it setting A=[[a,b],[c,d]] with 4 variables.
 
Sorry I'm not sure if I follow. So you're getting the same thing as me, where A is 4x3? How do I 'set' A to be four variables as opposed to 3?
 
DanielJackins said:
Sorry I'm not sure if I follow. So you're getting the same thing as me, where A is 4x3? How do I 'set' A to be four variables as opposed to 3?

All the matrices are 2x2. If I read your notation right A=a c b a mean A is a matrix with first row 'a c' and second row 'b a', right? There is no solution to your problem of that form because of the two 'a's in it. Change one of the 'a's to 'd' for example. Now you have four unknowns instead of three. Now there is a solution.
 
Won't that change the context of the question though?
 
DanielJackins said:
Won't that change the context of the question though?

Yes, it will. If you don't change the context then the answer is that there is no solution. Show that with your linear equations.
 
Problem is I can't, it's a web-based assignment and it expects me to input values for a, b, and c
 
Nevermind, I tried what you said and it worked out perfectly. Thanks a bunch!