Solve Max of sin(x) + sin(2x): Get Answer Now!

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SUMMARY

The maximum of the function Y = sin(x) + sin(2x) can be determined by finding the derivative and setting it to zero. The derivative dy/dx leads to a quadratic equation in cos(x) after substituting cos(2x) with 2cos²(x) - 1. Mathematica's FindMaximum function provides a numerical solution, yielding a maximum value of approximately 1.76017 at x ≈ 0.935929. This problem, while seemingly simple, requires careful application of calculus techniques.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Familiarity with trigonometric identities, particularly sin(2x) = 2sin(x)cos(x)
  • Knowledge of quadratic equations and their solutions
  • Experience with mathematical software, such as Mathematica
NEXT STEPS
  • Study the process of finding maxima and minima using derivatives
  • Learn about trigonometric identities and their applications in calculus
  • Explore solving quadratic equations in trigonometric contexts
  • Familiarize yourself with Mathematica's optimization functions, such as FindMaximum
USEFUL FOR

Students in calculus courses, mathematicians, and anyone interested in solving trigonometric optimization problems.

Constantinos
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This is not homework question, just curious about it though. This problem is supposed to be done without a computing device and was in an exam at a university course. I don't think it can be done.

Homework Statement


I want to find the maximum of this function:

Y = sin(x) + sin(2x)

Homework Equations


The Attempt at a Solution



Attempted sin(2x) = 2sinx*cosx, tried to draw it, tried to go euler's formula, no luck whatsoever (of course I take the derivative!)

Mathematica gives me this:

FindMaximum[Sin[x] + Sin[2*x], {x, 0}]

Out[1]= {1.76017, {x -> 0.935929}}

Any ideas? It really seems simple, but I just can't figure it out...

Thanks!
 
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Why don't you just solve dy/dx = 0 and then sub cos(2x) as 2cos2-1 ?

You should get a quadratic in cosx to solve.
 
rock.freak667 said:
Why don't you just solve dy/dx = 0 and then sub cos(2x) as 2cos2-1 ?

You should get a quadratic in cosx to solve.

Lol where is my mind! Thanks :P
 

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