Solve Mechanics Problem: Particle with Mass m and Resistive Force of mkv^2

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SUMMARY

The discussion centers on solving a mechanics problem involving a particle of mass m projected vertically upward with an initial speed u, subjected to gravity and a resistive force of magnitude mkv². The derived equation for the particle's velocity is v² = (g/k + u²)e^(-2kx) - g/k. Participants emphasize the necessity of integrating the equations of motion due to the variable acceleration caused by the resistive force, rather than applying the constant acceleration formula v² = u² + 2as.

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Homework Statement



A particle with mass m is projected vertically upwards from a point with speed u. THe particle, besides being subjected to gravity, experiences a resistive force of magnitude
mkv^2, with v as its velocity when its height from the point of projection is x and k as a positive constant. Show that

v^2=(\frac{g}{k}+u^2)e^{-2kx}-\frac{g}{k}

Homework Equations





The Attempt at a Solution



F-mkv-mg=ma

using v^2=u^2+2as

v^2=u^2-2gx

thats all i can get
 
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Did you know that the equation v^2 = u^2 + 2as only holds for constant acceleration? You will have to integrate in this case due to the varying acceleration.
 
Fightfish said:
Did you know that the equation v^2 = u^2 + 2as only holds for constant acceleration? You will have to integrate in this case due to the varying acceleration.

thanks , for this , do i integrate

F-mkv-mg=ma ?

am i supposed to get rid of some of the terms here first before i integrate ?
 

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