Solve Multi Var Limit: Help Appreciated!

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SUMMARY

The forum discussion centers on evaluating the limit of the function $$\lim_{(x, y) \to (0, 1)} \tan^{-1}\left[\frac{x^2 + 1}{x^2 + (y - 1)^2}\right]$$. Participants conclude that as (x, y) approaches (0, 1), the numerator approaches 1 while the denominator approaches 0 from the positive side, leading to the inside of the arctangent approaching +∞. Consequently, the overall limit is determined to be π/2. The discussion emphasizes the importance of understanding definitions and methods such as delta-epsilon proofs and the squeeze theorem in limit evaluation.

PREREQUISITES
  • Understanding of limits in multivariable calculus
  • Familiarity with the arctangent function and its properties
  • Knowledge of delta-epsilon definitions for limits
  • Experience with the squeeze theorem in calculus
NEXT STEPS
  • Study the delta-epsilon definition of limits in multivariable calculus
  • Learn about the properties of the arctangent function and its limits
  • Explore the squeeze theorem and its applications in proving limits
  • Practice evaluating limits of functions approaching indeterminate forms
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable limits, educators teaching limit evaluation techniques, and anyone seeking to strengthen their understanding of arctangent properties and limit proofs.

Scrope
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Homework Statement


afabe40fefbef53a39ed240e35d877cc
https://gyazo.com/268bef206850bfbf30fb0cca3f783599 <----- The question

Homework Equations

The Attempt at a Solution


Had this on a test today, honestly not sure how to evaluate. I know you can pass the limit to the inside of arctan but I can't see how the inside goes to infinity. Any help would be appreciated I just want to understand how to do it!
 
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I don't get infinity for the inside, either. What is the answer that they gave? Did they get pi/2 for the limit? What answer did you get for the inside (and the limit)?
 
the answer given is pi/2 for the overall answer and +infinity for the inside
 
The only advice I have received so far is to take note that the bottom is the square of the distance from (0,1) but I can’t figure out what they mean
 
Scrope said:

Homework Statement


afabe40fefbef53a39ed240e35d877cc
https://gyazo.com/268bef206850bfbf30fb0cca3f783599 <----- The question

Homework Equations

The Attempt at a Solution


Had this on a test today, honestly not sure how to evaluate. I know you can pass the limit to the inside of arctan but I can't see how the inside goes to infinity. Any help would be appreciated I just want to understand how to do it!
The numerator inside the brackets is approaching 1, and the denominator is approaching 0 from the positive side. It seems pretty clear to me that the part in brackets is approaching ##+\infty##, so the overall limit is what?
 
Mark44 said:
The numerator inside the brackets is approaching 1, and the denominator is approaching 0 from the positive side. It seems pretty clear to me that the part in brackets is approaching ##+\infty##, so the overall limit is what?

the way I had learned it was that the only way to prove a limit existed was through methods such as delta-epsilon definition, switching to R or Rho, or by squeeze theorem. Is there any mathematical way to show that this goes to +infinity? We were told we were unable to evaluate limits by observation.
 
Scrope said:
the way I had learned it was that the only way to prove a limit existed was through methods such as delta-epsilon definition, switching to R or Rho, or by squeeze theorem. Is there any mathematical way to show that this goes to +infinity? We were told we were unable to evaluate limits by observation.
For the record, here is the limit in the image link you posted:
$$\text{Find }\lim_{(x, y) \to (0, 1)} \tan^{-1}\left[\frac{x^2 + 1}{x^2 + (y - 1)^2}\right]$$
The problem asks you to find the limit, but doesn't ask you to prove that this value is the limit. Proving the limit would require the use of a delta-epsilon proof or a theorem such as the squeeze theorem.

A major difficulty with these kinds of limits is when the limit is an indeterminate form such as ##[\frac 0 0]##. This limit is not one of the indeterminate forms, since the numerator approaches 1 and the denominator approaches 0 through the positive numbers.
 
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Scrope said:
the way I had learned it was that the only way to prove a limit existed was through methods such as delta-epsilon definition, switching to R or Rho, or by squeeze theorem. Is there any mathematical way to show that this goes to +infinity? We were told we were unable to evaluate limits by observation.

Yes, the way to do it is to use the definition of the notion ##(x,y) \to (0,1)##. Just using that definition (and a few simple manipulations), it is easy to show that for any (large) number ##N > 0##, we know that as ##(x,y)## nears ##(0,1)## (in a well-defined sense that you are supposed to know) we have that the denominator of the inside fraction becomes ##< 1/N##. The numerator is ## \geq 1##, so the inside fraction is ##> N##. That is essentially the definition of ##\text{fraction} \to +\infty.##
 
Mark44 said:
For the record, here is the limit in the image link you posted:
$$\text{Find }\lim_{(x, y) \to (0, 1)} \tan^{-1}\left[\frac{x^2 + 1}{x^2 + (y - 1)^2}\right]$$
The problem asks you to find the limit, but doesn't ask you to prove that this value is the limit. Proving the limit would require the use of a delta-epsilon proof or a theorem such as the squeeze theorem.

A major difficulty with these kinds of limits is when the limit is an indeterminate form such as ##[\frac 0 0]##. This limit is not one of the indeterminate forms, since the numerator approaches 1 and the denominator approaches 0 through the positive numbers.
Oh, that's easier to read than the tiny image. I misread what x and y we're approaching.
 
  • #10
It doesn't matter whether the 'inside' is +∞ or -∞ , its tan-1 is π/2 in either case.

You appear to be able to approach the limit in several ways including from y>1.

The denominator is indeed the squared distance of a point (x, y) from (0,1).
 
  • #11
epenguin said:
It doesn't matter whether the 'inside' is +∞ or -∞ , its tan-1 is π/2 in either case.
Not so. ##\lim_{x \to -\infty}\tan^{-1}(x) = -\frac \pi 2##. For this inverse trig function, the restricted-domain function ##y = \tan(x), -\frac \pi 2 < x < \frac \pi 2## is used.
 

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