Solve Physics Problem: 3000kg Space Capsule

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SUMMARY

The problem involves a 3000 kg space capsule traveling at 200 m/s that fires a 25 kg projectile at 2000 m/s perpendicular to its motion. Using the conservation of momentum equation, the final speed of the capsule is calculated to be 1833.3 m/s. The direction change angle requires further calculations, potentially involving Pythagorean theorem principles. The assumption that the mass of the capsule remains constant is critical for applying momentum conservation accurately.

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Homework Statement



A 3000kg space capsule is traveling with a velocity of 200m/s. In an effort to alter its course, it fires a 25.0 kg projecticle perpendicular to its original direction of motion at a speed of 2000 m/s. What is the speed of the capsule and by what angle has its direction changed.

* my teacher said assume mass stays the same*

Homework Equations



P = mv
m1v1 + m2v2 = m1v1' + m2v2'
M = m1 + m2
V = combined velocity

The Attempt at a Solution



MV = m1v1' + m2v2'
(3000)(200) = (3000)(v1') + (25)(2000)
v1' = 1833.3

Is this right so far? I'm very confused and am not sure if I should be using Pythagoras to find it or what?
 
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Can anyone please help me out? I've been stuck on this question for over half an hour. :(
 

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