Solve polynomial using complex number

Click For Summary
SUMMARY

The discussion focuses on solving polynomial equations using complex numbers, specifically addressing two problems: (a) solving w3 = 1 in de Moivre form and (b) using the result from (a) to solve (z + i)3 + (z - i)3 = 0. The key insight is to divide both sides of equation (b) by (z + i)3 and recognize that -1 can be expressed as (-1)3, allowing the equation to be rewritten as (i - z)/(i + z)3 = 1, thus linking the two problems.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with de Moivre's Theorem
  • Basic algebraic manipulation skills
  • Knowledge of polynomial equations
NEXT STEPS
  • Study de Moivre's Theorem in detail
  • Learn how to manipulate complex fractions
  • Explore polynomial roots and their geometric interpretations
  • Investigate the properties of cubic equations
USEFUL FOR

Students and educators in mathematics, particularly those focusing on complex numbers and polynomial equations, as well as anyone preparing for advanced algebra or calculus courses.

songoku
Messages
2,514
Reaction score
395
Homework Statement
a. Solve w^3 = 1 in de moivre form

b. You must use result from (a) to solve (z + i)^3 + (z - i)^3 = 0
Relevant Equations
de moivre
I can do question (a). For question (b), I can not see the relation to question (a). Can we really do question (b) using result from (a)? Please give me little hint to relate them

Thanks
 
Physics news on Phys.org
songoku said:
Homework Statement: a. Solve w^3 = 1 in de moivre form

b. You must use result from (a) to solve (z + i)^3 + (z - i)^3 = 0
Homework Equations: de moivre

I can do question (a). For question (b), I can not see the relation to question (a). Can we really do question (b) using result from (a)? Please give me little hint to relate them

Thanks

Divide both sides in (b) by ##(z+i)^3## and use that ##-1=(-1)^3## to write the equation in the form

$$\left(\frac{i-z}{i+z}\right)^3=1$$

Then you can use (a) to proceed.
 
Math_QED said:
Divide both sides in (b) by ##(z+i)^3## and use that ##-1=(-1)^3## to write the equation in the form

$$\left(\frac{i-z}{i+z}\right)^3=1$$

Then you can use (a) to proceed.

Thank you very much
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 0 ·
Replies
0
Views
3K
Replies
4
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
8K
Replies
9
Views
2K
  • · Replies 26 ·
Replies
26
Views
2K