Solve PV Module Problem: Find I,V,P for 3 Conditions

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The discussion revolves around calculating the current (I), voltage (V), and power (P) for a photovoltaic (PV) module under three conditions: full sunlight, one cell in shade, and two cells in shade. The module consists of 40 cells in series, each producing 0.5 volts, resulting in a total of 20 volts in full sunlight. When one cell is shaded, the voltage drops to 19.5 volts, and the shaded cell behaves like a 5-ohm resistor due to its inability to generate power, which is attributed to its semiconductor properties. The resistance of the shaded cell is based on empirical measurements, and the module's design includes bypass diodes to protect against the effects of shading. Understanding these principles is crucial for accurately calculating the performance of PV modules under varying conditions.
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Im working on a problem that involves a PV module consisting of 40 cells each at .5 volts. The problem models the module as having all 40 cells in series. The PV module is connected to a 5 ohm load. The problem also says to assume that the same current and voltage flows through the PV module and load. So solve for I, V, and P.

I just need to find the current, power, and voltage for 3 conditions.

a) when in full sunlight

b) when 1 cell is in shade

c) when 2 cells are in shade.


my question is:

I know the voltage to be 20 volts in full sunlight and 19.5 volts when 1 cell is in shade...so when 1 cell is in shade I noticed the book saying that one .5 volt cell will now act as a 5 ohm reisistor...is this true...and why?

and if that is the case for 1 cell in the shade would I have a total of 10 ohms resistance to calculate the current flowing?
 
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any ideas?...I can understand a cell not functioning acting as a resistor...but why 5 ohms?
 
Jason03 said:
any ideas?...I can understand a cell not functioning acting as a resistor...but why 5 ohms?

I would guess it is because that's what someone measured when they shaded an individual cell. Silicon is a semiconductor, so with no light falling on the cell, it turns into a resistor. That resistance will depend on the physical dimensions of the cell.
 
its true , for this case the PV module must protect it by bypass diode
 
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