The discussion focuses on solving a quadratic equation without the use of a computer, specifically calculating the sum of squares of the digits in the decimal representation of a fraction. The fraction given is $\frac{1234567891011121314151617}{7161514131211101987654321}$, which approximates to $0.1723$. Through manual calculations and approximations, the digits $a=1$, $b=7$, and $c=2$ are identified, leading to the conclusion that $a^2 + b^2 + c^2 = 54$.
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[sp]Reminds me of http://mathhelpboards.com/pre-algebra-algebra-2/when-0-123-495051-0-515049-321-a-6136.html. First step is to check that numerator and denominator have the same number of digits (25). Then my little pocket calculator (assuming that I'm allowed to use it) gives the approximations as $$\frac{1234}{7161}\approx 0.1723,$$ $$\frac{12345678}{71615141} \approx 0.17238.$$ It looks as though the first three digits are $1,\ 7,\ 2$, with $1^2+7^2+2^2 = 54.$ I have not tried to prove this carefully as in that previous thread.[/sp]Albert said:$\dfrac {1234567891011121314151617}
{7161514131211101987654321}=0.abc----$
please find :$a^2+b^2+c^2=? $
(use of computer is not allowed!)
Let: $\dfrac{1234}{7162}<A=\dfrac {1234567891011121314151617}Albert said:$\dfrac {1234567891011121314151617}
{7161514131211101987654321}=0.abc----$
please find :$a^2+b^2+c^2=? $
(use of computer is not allowed!)