Solve Quadratic Equations: Calculate Equation of Curve

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SUMMARY

The discussion focuses on calculating the equation of a quadratic curve using the general form y=ax²+bx+c, where a≠0. It highlights the vertex form y=a(x-k)²+q, which provides the vertex (k,q) of the parabola. To derive the quadratic equation, a minimum of three points is required, allowing for the creation of a system of linear equations to solve for the coefficients a, b, and c. This method ensures accurate representation of parabolas, which are characterized by their vertical axes in the context of quadratic functions.

PREREQUISITES
  • Understanding of quadratic equations and their properties
  • Familiarity with linear equations and systems of equations
  • Knowledge of the vertex form of a quadratic equation
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation and applications of the quadratic formula
  • Explore the properties of parabolas and their transformations
  • Learn how to graph quadratic functions using software tools like Desmos
  • Investigate real-world applications of quadratic equations in physics and engineering
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Students, educators, and professionals in mathematics, engineering, and physics who require a solid understanding of quadratic equations and their applications in various fields.

matt_crouch
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how do you calculate the equation of a quadratic curve. A straight line curve uses
y-y1=m(x-x1) is i an alteration of this line?
cheers
 
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Actually there are multiple ways of expressing lines, quadratics etc.

The general form is
[tex]y=ax^2+bx+c[/tex] where [tex]a\neq 0[/tex]
This is efficient because it is translated into the quadratic formula easily.

There is also the vertex form
[tex]y=a(x-k)^2+q[/tex]
This form quickly gives the vertex (k,q) of the parabola.

etc.

To calculate the equation of a quadratic, you need 3 points minimum. If you know it's a parabola then you will also know it can be expressed in the general form [tex]y=ax^2+bx+c[/tex]
If one of the points given to you lie on the parabola, then the point satisfies the quadratic. i.e. you can substitute the x and y value of the point into the general form.
Lets say its (2,3)
Then [tex]3=4a+2b+c[/tex] which is a linear equation with 3 variables.
Once you do this for all 3 points, you will have 3 equations with 3 variables. Thus, you can solve them simultaneously to find the values of a, b and c.

These values can then be plugged back into the general form to give you your parabola.
 
Those are the formulas for quadratic functions- whose graphs are parabolas with vertical axis. You can have parabolas at any angle to the axes but then they are not the graphs of functions.
 

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