Actually there are multiple ways of expressing lines, quadratics etc.
The general form is
[tex]y=ax^2+bx+c[/tex] where [tex]a\neq 0[/tex]
This is efficient because it is translated into the quadratic formula easily.
There is also the vertex form
[tex]y=a(x-k)^2+q[/tex]
This form quickly gives the vertex (k,q) of the parabola.
etc.
To calculate the equation of a quadratic, you need 3 points minimum. If you know it's a parabola then you will also know it can be expressed in the general form [tex]y=ax^2+bx+c[/tex]
If one of the points given to you lie on the parabola, then the point satisfies the quadratic. i.e. you can substitute the x and y value of the point into the general form.
Lets say its (2,3)
Then [tex]3=4a+2b+c[/tex] which is a linear equation with 3 variables.
Once you do this for all 3 points, you will have 3 equations with 3 variables. Thus, you can solve them simultaneously to find the values of a, b and c.
These values can then be plugged back into the general form to give you your parabola.