Solve Quadratic Inequality: x²-4x+3≤(3x+5)(2x-3)

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SUMMARY

To solve the quadratic inequality x²-4x+3≤(3x+5)(2x-3), first simplify the inequality by expanding the right side using the FOIL method. This results in the expression x²-4x+3≤6x²-9x+15. Rearranging the terms leads to a standard form quadratic inequality. The critical values, which are the roots of the resulting quadratic expression, can then be determined to analyze the three intervals on x for solutions.

PREREQUISITES
  • Understanding of quadratic equations and inequalities
  • Familiarity with the FOIL method for binomial multiplication
  • Knowledge of critical points and interval testing
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Practice solving quadratic inequalities with different coefficients
  • Learn about interval testing for inequalities
  • Explore the relationship between roots and the sign of quadratic expressions
  • Study the graphical representation of quadratic functions and their inequalities
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Students studying algebra, particularly those tackling quadratic inequalities, as well as educators looking for examples to illustrate solving techniques in mathematics.

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Homework Statement



How to solve this kind of inequality?
x²-4x+3≤(3x+5)(2x-3)

Homework Equations

The Attempt at a Solution

:[/B]
I'm confused. Should I factor the left side or should I FOIL the right side then equate it to zero to find the critical numbers? Help pleaasee.
 
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Simplify the inequality and arrange for all terms to be on one side and 0 on the other side. The quadratic inequality can then be examined for the three intervals on x. The critical values will be the roots of the simplified quadratic expression.
 

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