Solve Rectangular Room Mirror Homework Problem

  • Thread starter Thread starter Shibos
  • Start date Start date
  • Tags Tags
    Homework Mirror
Click For Summary
To solve the rectangular room mirror problem, visualize the reflection of the room as if the mirror were a window. This approach allows for straight-line diagrams, simplifying the analysis of how light travels from the person's eyes to the image of the back wall. The person standing 0.5 m in front of the mirror can see both ends of the back wall, indicating that the mirror's width and the distance from the person to the mirror are crucial for determining the wall's length. By applying geometric principles to the reflection, one can calculate the necessary dimensions. Understanding this concept is key to finding the solution.
Shibos
Messages
1
Reaction score
0

Homework Statement



A rectangular room is 6 m long. A mirror 0.35 m wide is hung on the wall horizontally at one end of the room. A person standing 0.5 m in front of the mirror can just see both ends of the back wall in the mirror. What is the length of the back wall.

I don't want the answer I just want to know how to get it. explain everything please!

Homework Equations



N/A

3. The Attempt at a Solution [/b

Don't have a clue how to attempt it.
 
Physics news on Phys.org
Welcome to PF!

Hi Shibos! Welcome to PF! :smile:

The best way to solve (flat) mirror questions is usually to draw the reflection (the image) of the room on the "wrong" side of the mirror (so that the mirror turns into a window :wink:) …

that means that instead of bent lines in your diagram, you can just draw straight lines, from the eye (on the "right" side) to the image! :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
3
Views
5K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
3
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
10
Views
26K