Solve Refracted Ray Problem: Find Angle of Refraction

[carpelumen]

1.
I figured out the first few, I just can't get the last one!

-The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material?
1.54

-A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).
37.9 deg

-Calculate the angle of the refracted ray (in degrees).
23.5 deg

Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray?
?

Homework Equations

Refractive index x sin (theta)

The Attempt at a Solution

[/B]
1.54 x sin (37.9) = .945999What am I doing wrong?

 

[nasu]

Do you know Snell's law? What you wrote there is incomplete. Wrote the complete law.

 

[carpelumen]

I figured it out. Thanks