- #1
MikkelR
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I'm kinda stuck in this mechanical problem, ill try to describe the situation.
A plane, homogeneous disk may slide on a frictionless horizontal table. A cord is fastened to the disc and wrapped many times around the rim of the disc. The cord goes without friction through a small eyelet at the edge of the table and is connected to a mass m. The mass of the disc is M and its radius is R. The system is started from rest and the cord is assumed to be taut throughout the motion. Ignore the mass of the cord.
http://ylle.eu/DSC00602.JPG (my sketch of the problem)
Describe the velocity of the disc as a function of time.
Here is what i have computed of equations so far.
The forces affecting the disc M must be M(d²x)/(dt²) = mg
The forces affecting the mass m must be m(d²x)/(dt²) = mg - S
The torque(N) exerted on M can be described as
N = mgR
The moment of inertia for a circular disk around its CM is
I = (1/2)MR²
The angular momentum is
L = Iw
Torque equals the change of angular momentum with respect to time
N = Iw'
N = (1/2)MR²w'
mgR = (1/2)MR²w'
And from this point i can't really seem to maky any more observations that can help me solve the problem.
I hope someone can clarify the problem for me
Thanks in advance
Mikkel
A plane, homogeneous disk may slide on a frictionless horizontal table. A cord is fastened to the disc and wrapped many times around the rim of the disc. The cord goes without friction through a small eyelet at the edge of the table and is connected to a mass m. The mass of the disc is M and its radius is R. The system is started from rest and the cord is assumed to be taut throughout the motion. Ignore the mass of the cord.
http://ylle.eu/DSC00602.JPG (my sketch of the problem)
Describe the velocity of the disc as a function of time.
Here is what i have computed of equations so far.
The forces affecting the disc M must be M(d²x)/(dt²) = mg
The forces affecting the mass m must be m(d²x)/(dt²) = mg - S
The torque(N) exerted on M can be described as
N = mgR
The moment of inertia for a circular disk around its CM is
I = (1/2)MR²
The angular momentum is
L = Iw
Torque equals the change of angular momentum with respect to time
N = Iw'
N = (1/2)MR²w'
mgR = (1/2)MR²w'
And from this point i can't really seem to maky any more observations that can help me solve the problem.
I hope someone can clarify the problem for me
Thanks in advance
Mikkel