Solve Series S_n: 1056, 1088, 1120, 1332

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The series S_n is defined as S_n = ∑_{k=1}^{4n} {(-1)^{\frac{k(k+1)}{2}}} {k^2}. The values that S_n can take include 1056, 1088, 1120, and 1332. It is observed that as n increases by 1, the series adds four new terms, consisting of two negative and two positive contributions. For n=1, the sum equals 20, and for n=2, the sum equals 72, illustrating a pattern in the series' growth.

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[tex]S_n = \sum_{k=1}^ {4n} {(-1)^\frac{k(k+1)}{2}} {k^2}[/tex].

Then Sn can take what values among:
1056, 1088, 1120, 1332
 
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hi klen! :wink:

simplest way is probably to do the sum for 4m-3,4m-2,4m-1,4m (only) first …

what do you get? :smile:
 
klen said:
[tex]S_n = \sum_{k=1}^ {4n} {(-1)^\frac{k(k+1)}{2}} {k^2}[/tex].

Then Sn can take what values among:
1056, 1088, 1120, 1332

Did you, for example, notice that every time n increases by 1, the sum has 4 new terms, two negative and two positive? Do you notice that for n= 1, so there are 4 terms, the sum is 20= 4(5) and when n= 2, so there are 8 terms, the sum is 72= 8(9)?
 

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