Solve Spring Equilibrium Homework: Find a-g | Physics

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SUMMARY

The discussion centers on a physics problem involving a mass (m = 1.20 kg) attached to a spring (k = 790 N/m) and the effects of an additional constant force on the system's equilibrium position. The key points include the calculation of work done by the constant force, the change in potential energy of the spring, and the implications of the force on the equilibrium position. The participant seeks clarification on why the equilibrium position changes when a constant force is applied, emphasizing the relationship between force, displacement, and dynamic equilibrium.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Knowledge of potential energy in elastic systems
  • Familiarity with concepts of equilibrium in physics
  • Basic principles of mechanics and forces
NEXT STEPS
  • Study the implications of Hooke's Law on spring systems
  • Explore the concept of dynamic equilibrium in physics
  • Learn about energy conservation in mechanical systems
  • Investigate the effects of external forces on equilibrium positions
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Students studying physics, particularly those focusing on mechanics and harmonic motion, as well as educators looking for examples of spring dynamics and equilibrium concepts.

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Homework Statement


A mass (m = 1.20 kg), originally at rest, is attached to one end of an unstretched spring (k = 790 N/m) and the other end is fixed to a wall. The mass is then pulled with a constant force to stretch the spring. As a result, the system comes to a momentary stop after the mass is moved 14.0 cm. Find the:
a) work done by the constant force
b) change in potential energy of the spring --same answer as a)
c) change in mechanical energy of the system --same answer as a)
d) total work done by non-conservative forces --same answer as a)
e) speed of the mass 4.00 cm into the motion
f) the new equilibrium position of the system
g) maximum speed of the mass and where it occurs

The only question I have so far is f): why would the equilibrium position change? I am just looking for a conceptual answer here.
Note: there is no friction anywhere

Homework Equations


N/A

The Attempt at a Solution


N/A
 
Last edited:
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think of the "additional constant force" like increasing the original mass. Since F = -kx, greater force means more displacement to get to equilibrium
 
I should add that there is no friction anywhere*
As far as I understand, equilibrium refers to the mean displacement of the simple harmonic motion. Though now I think equilibrium refers to dynamic equilibrium between forces. Is this correct?
 

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