Solve Stokes' 2 Homework with Flux Calculation

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SUMMARY

The discussion revolves around solving a homework problem using Stokes' theorem to evaluate the flux through a closed surface formed by the intersection of a sphere and the plane z=2. The user initially misinterprets the problem by considering the entire sphere as the surface, but later clarifies that the relevant closed curve is a circle at z=2. Participants emphasize the importance of parametrizing the correct surface and suggest using Stokes' theorem to compute the flux through the closed surface bounded by this circle.

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  • Understanding of Stokes' theorem
  • Knowledge of vector calculus, specifically curl and flux
  • Familiarity with parametrization of surfaces
  • Basic concepts of closed curves and line integrals
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Homework Statement



Ok, so I need to solve this integral (bottom of the pic) using Stokes' theorem.
What I did first is to find the Curl, then I used the UV surface as usual and then found the normal.
After that, I switched to an area integral of the dot product between the curl and the normal over the UV surface.
It's all in the pic.
My question is this, what this integral actually finds is the flux, right? the flux that goes through the Spiral, so if it's correct, do I also need to find the flux that goes through the plot z=2, that goes downward?

Damn, my English sucks :smile:

Homework Equations





The Attempt at a Solution

:smile:
 

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Any idea, guys?
 
Defennder said:
I don't see any spiral. The integral is meant to evaluate the flux through a closed surface by the divergence theorem. I go zero as well. What do you mean by the plot where z=2?

Do u mean using Gauss' law?
 
Oh shucks I just responded to the wrong thread! This is meant for the other thread.
 
Ok I still don't see what spiral you're talking about. You're evaluating the closed line integral corresponding to the closed curve interesection between the sphere and the plane z=2. So, you found curl F, but you seem to have taken the surface to be the sphere itself. While it's still possible, it makes for tedious calculation. Pick an easier surface to parametrise.
 
Defennder said:
Ok I still don't see what spiral you're talking about. You're evaluating the closed line integral corresponding to the closed curve interesection between the sphere and the plane z=2. So, you found curl F, but you seem to have taken the surface to be the sphere itself. While it's still possible, it makes for tedious calculation. Pick an easier surface to parametrise.

Sorry, I meant sphere, I said my English sucks.
Anyway, I need to find the flux that comes out of this surface between Z=2 and the sphere, and I don't think I can parametrize both of them together, should I use Gauss' law?
10x.
 
Yeah, I mean the surface is a closed surface, it's between the plot z = 2 and the sphere, so I thought maybe I can use Gauss' law somehow, no?
 
No, you're supposed to evaluate the closed line integral formed by the intersection of the plane and the sphere. That is if I interpret \oint correctly to mean a line integral on a closed path. You should pick an easy surface bound by this closed curve to parametrise. There's only one surface to parametrise. And I still don't know what you mean by Gauss law.

EDIT: It's not a closed surface. Otherwise you can't use Stoke's theorem.
 
Defennder said:
No, you're supposed to evaluate the closed line integral formed by the intersection of the plane and the sphere. That is if I interpret \oint correctly to mean a line integral on a closed path. You should pick an easy surface bound by this closed curve to parametrise. There's only one surface to parametrise. And I still don't know what you mean by Gauss law.

EDIT: It's not a closed surface. Otherwise you can't use Stoke's theorem.

I don't get it, the intersection of the plane and the sphere is the circle in Z=2, should I parametrize it?
 
  • #10
Oh, is it the circle?
 
  • #11
Yes the circle is the closed curve. You can evaluate the line integral directly or use stokes theorem to calculate the flux through any closed surface bound by the circle.
 
  • #12
Defennder said:
Yes the circle is the closed curve. You can evaluate the line integral directly or use stokes theorem to calculate the flux through any closed surface bound by the circle.

Oh, I was way off, I thought I need to find the flux through part of the sphere (from Z=2 up to the top) which is not even a line...:redface:
That's way I talked about guess's low.
Ok, thanks a lot.
 
  • #13
Is that right?
 

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